Which of the following statements indicates that light waves are transverse? 

1.	Light waves can travel in a vacuum.
2.	Light waves show interference.
3.	Light waves can be polarized.
4.	Light waves can be diffracted.

Interference was observed in interference chamber when the air was present, now the chamber is evacuated and if the same light is used, a careful observer will see

(1) No interference

(2) Interference with bright bands

(3) Interference with dark bands

(4) Interference in which width of the fringe will be slightly increased

Ray diverging from a point source forms a wavefront that is:

1. cylindrical.

2. spherical.

3. plane.

4. cubical.

Two coherent sources have intensity in the ratio of $\frac{100}{1}$. Ratio of (intensity)_max/(intensity)_min is: 
1. $\frac{1}{100}$
2. $\frac{1}{10}$
3.$\frac{10}{1}$
4. $\frac{3}{2}$

If two waves represented by $y_1=4\sin \omega t$ and $y_2=3\sin \left(\omega t+\frac{{\displaystyle \pi }}{{\displaystyle 3}}\right)$ interfere at a point, the amplitude of the resulting wave will be about 

(1) 7

(2) 6

(3) 5

(4) 3.5

Two coherent sources of intensities, I₁ and I₂ produce an interference pattern. The maximum intensity in the interference pattern will be 

(1) I₁ + I₂

(2) $I_1^2+I_2^2$

(3) (I₁ + I₂)²

(4) ${(\sqrt{I_1}+\sqrt{I_2})}^2$

Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is $\frac{\pi }{2}$ at point A and π at point B. Then the difference between the resultant intensities at A and B is 

(1) 2I

(2) 4I

(3) 5I

(4) 7I

If an interference pattern has maximum and minimum intensities in a 36 : 1 ratio, then what will be the ratio of their amplitudes?

1. 5 : 7

2. 7 : 4

3. 4 : 7

4. 7 : 5

In Young's double slit experiment, if the slit widths are in the ratio \(1:9,\) then the ratio of the intensity at minima to that at maxima will be:
1. \(1\)
2. \(1/9\)
3. \(1/4\)
4. \(1/3\)

In a certain double slit experimental arrangement interference fringes of width 1.0 mm each are observed when light of wavelength 5000 Å is used. Keeping the set up unaltered, if the source is replaced by another source of wavelength 6000 Å, the fringe width will be 

(1) 0.5 mm

(2) 1.0 mm

(3) 1.2 mm

(4) 1.5 mm