1g of pure calcium carbonate was found to require 50 mL of dilute HCl for complete reactions. The strength of the HCl solution is given by:

1. 4N

2. 2N

3. 0.4N

4. 0.2N

Subtopic:  Equivalent Weight |
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The equivalent mass of H3PO4 in the following reaction is,

H3PO+ Ca(OH)2 CaHPO4 + 2H2O

1. 98

2. 49

3. 32.66

4. 40

Subtopic:  Equivalent Weight |
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1.520g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent mass of metal is:

1. 1.520

2. 0.995

3. 19.00

4. 9.00

Subtopic:  Equivalent Weight |
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0.5 g of fuming H2SO4 (oleum) is diluted  with water. This solution is completely neutralised by 26.7 mL of 0.4 N NaOH. The percentage of free SO3 in the sample is:

1. 30.6% 

2. 40.6%

3. 20.6%

4. 50%

Subtopic:  Equivalent Weight |
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One g of a mixture of Na2CO3 and NaHCO3 consumes y equivalent of HCl for complete neutralisation. One g of the mixture is strongly heated, then cooled and the residue treated with HCl. How many equivalent of HCl would be required for complete neutralisation?

1. 2y equivalent

2. y equivalent

3.  3y/4 equivalent

4. 3y/2 equivalent

Subtopic:  Equivalent Weight |
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The chloride of a metal contains 71% chlorine by mass and the vapour density of it is 50. The atomic mass of the metal will be:

1. 29

2. 58

3. 35.5

4. 71

Subtopic:  Equivalent Weight |
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The equivalent mass of Zn(OH)2 in the following reaction is equal to its,

Zn(OH)2 + HNO3 Zn(OH)(NO3) + H2O :

1. Formula mass/1

2. Formula mass/2

3. 2 x formula mass

4. 3 x formula mass

Subtopic:  Equivalent Weight |
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What will be the normality of a solution obtained by mixing 0.45 N and 0.60 N NaOH in the ratio 2:1 by volume?

1. 0.4 N

2. 0.5 N

3. 1.05 N

4. 0.15 N

Subtopic:  Equivalent Weight |
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0.7 g of Na2CO3.xH2O were dissolved in water and the volume was made to 100mL, 20mL of this solution required 19.8 mL of N/10 HCl for complete neutralization. The value of x is:

1. 7

2. 3

3. 2

4. 5

Subtopic:  Equivalent Weight |
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A metal oxide is reduced by heating it in a stream of hydrogen. It is found that after complete reduction, 3.15 g of the oxide have yielded 1.05g of the metal. We may deduce that:

1. the atomic mass of the metal is 8

2. the atomic mass of the metal is 4

3. the equivalent mass of the metal is 4

4. the equivalent mass of the metal is 8

Subtopic:  Equivalent Weight |
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