Metals have conductivity of the order of (ohm^-1 m^-1):-

1. 10¹²

2. 10⁸

3. 10²

4. 10^-6

An electrochemical cell is shown below Pt, H₂(1 atm)| HCI (0.1 M)CH₃COOH (0.1 M)|

H₂(1 atm), Pt The EMF of the cell will not be zero, because

1. EMF depends on molarities of acids used

2. pH of 0.1 M HCl and 0.1 M CH₃COOH is not same

3. the temperature is constant

4. acids used in two compartments are different

Saturated solution of KNO₃ is used to make 'salt-bridge' because:

1. velocity of K⁺ is greater than that of ${\mathrm{NO}}_3^{-}$

2. velocity of ${\mathrm{NO}}_3^{-}$ is greater than that of K⁺

3. Velocities of both K⁺ and ${\mathrm{NO}}_3^{-}$ are nearly the same

4. KNO₃ is highly soluble in water

A current is passed through two voltameters connected in series. The first voltmeter connected in series. The first voltmeter contains XSO₄(aq) while the second voltmeter contains Y₂SO₄(aq). The relative  atomic masses of X and Y are in the ratio of 2:1. The ration of the mass of X liberated to the mass of Y liberated is: 

1. 1:1

2. 1:2

3. 2:1

4. none of these

At 25 °C molar conductance of 0.1 molar aqueous solution of ammonium hydroxide is 9.54 Ω^-1 cm² mol^-1 and at infinite dilution its molar conductance is 238 Ω^-1 cm² mol^-1. The degree of ionisation of ammonium hydroxide at the same concentration and temperature is :

Which is the correct representation for Nernst equation ?

1. \(E_{\mathrm{RP}}=E_{\mathrm{RP}}^{\circ}+\frac{0.059}{\mathrm{n}} \log \frac{[\text { oxidant }]}{[\text { reductant }]}\)

2. \(E_{\mathrm{OP}}=E_{\mathrm{OP}}^{\circ}-\frac{0.059}{\mathrm{n}} \log \frac{[\text { oxidant }]}{[\text { reductant }]}\)

3. \(E_{\mathrm{OP}}=E_{\mathrm{OP}}^{\circ}+\frac{0.059}{\mathrm{n}} \log \frac{[\text { reductant }]}{[\text { oxidant }]}\)

4. All of the above

When a copper wire is immersed in a solution of AgNO₃, the colour of the solution becomes blue because copper:

1. Forms a soluble complex with \(AgNO_3\)
2. Is oxidised to \(Cu^{2+}\)
3. Is reduced to \(Cu^{2-}\)
4. Splits up into atomic form and dissolves

The specific conductance of a 0.1 M KCl solution at 23 °C  is 0.012  Ω^-1 cm^-1 . The resistance of cells containing the solution at the same temperature was found to be 55 Ω. The cell constant will be:

Given below are the half-cell reactions,

Mn²⁺ + 2e^-  $\to \; Mn; \; \; \; \; \; \; E0\; =\; -1.18V$

$$ \to \; 2Mn2+; \; E0\; =\; +1.51V$$

$$ E0 for\; 3\; Mn2+ \to \; 2\; Mn+3 \; +$$Mn will be:

$$ $ 1.\; -2.69V;\; the\; reaction\; will\; not\; occur$$$

$$ $ 2.\; -2.69V;\; the\; reaction\; will\; occur$$$

$$ $ $ 3.\; -0.33V;\; the\; reaction\; will\; not\; occur$$$$

$$ $ $ $ 4.\; -0.33V;\; the\; reaction\; will\; occur$$$$$

E⁰ for Fe²⁺ + 2e → Fe is -0.44 volt and E⁰ for Zn²⁺ + 2e→ Zn is -0.76 volt, thus:

1. Zn is more electropositive than Fe

2. Fe is more electropositive than Zn

3. Zn is more electronegative

4. none of the above