The amplitude of a particle executing SHM is 4 cm. At the mean position the speed of the particle is 16 cm/sec. The distance of the particle from the mean position at which the speed of the particle becomes 83cm/sec will be

(1)         23cm             

(2)  3cm

(3)         1 cm                   

(4)  2 cm

Subtopic:  Simple Harmonic Motion |
 70%
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The maximum velocity of a simple harmonic motion represented by y=3 sin 100t+π6 is given by

(1)       300       

(2)   3π6

(3)      100         

(4)   π6

Subtopic:  Simple Harmonic Motion |
 93%
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The displacement equation of a particle is x=3sin 2t+4cos 2t  The amplitude and maximum velocity will be respectively

(a) 5, 10      

(b) 3, 2

(c) 4, 2       

(d) 3, 4

Subtopic:  Simple Harmonic Motion |
 90%
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The instantaneous displacement of a simple pendulum oscillator is given by x=A cos ωt+π4 . Its speed will be maximum at time

(1) π4ω      

(2) π2ω

(3) πω                

(4) 2πω

Subtopic:  Simple Harmonic Motion |
 61%
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The amplitude of a particle executing S.H.M. with frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is

(a)      144π2m/sec2        (b)     144m/sec2

c)      144π2m/sec2           (d)     288π2m/sec2   

Subtopic:  Simple Harmonic Motion |
 88%
From NCERT
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A particle moving along the x-axis executes simple harmonic motion, then the force acting on it is given by

(1)   – A Kx           

(2)   A cos (Kx)

(3)   A exp (– Kx

(4)   A Kx

Subtopic:  Simple Harmonic Motion |
 84%
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What is the maximum acceleration of the particle doing the SHM y=2sinπt2+ϕ where 2 is in cm

(a)  π2cm/s2                 (b)    π22cm/s2

(c)    π4cm/s2               (d)    π4cm/s2

Subtopic:  Simple Harmonic Motion |
 92%
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A particle executes simple harmonic motion along a straight line with an amplitude A. The potential energy is maximum when the displacement is

(1)     ±A          

(2)    Zero

(3)     ±A2         

(4)   ±A2

Subtopic:  Energy of SHM |
 81%
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The potential energy of a particle with displacement X depends as U(X). The motion is simple harmonic, when (K is a positive constant)

(1) U=KX22                 

(2) U=KX2   

(3)  U=K                       

(4) U=KX 

Subtopic:  Energy of SHM |
 81%
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The angular velocity and the amplitude of a simple pendulum is ω and a respectively. At a displacement X from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to V is 

(1)     X2ω2a2-X2ω2       

(2)    X2/a2-x2

(3)   a2-X2ω2/X2ω2       

(4)   (a2-x2)/X2

Subtopic:  Energy of SHM |
 78%
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