The instantaneous displacement of a simple pendulum oscillator is given by x=A cos ωt+π4 . Its speed will be maximum at time

(1) π4ω      

(2) π2ω

(3) πω                

(4) 2πω

Subtopic:  Simple Harmonic Motion |
 61%
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The amplitude of a particle executing S.H.M. with frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is

(a)      144π2m/sec2        (b)     144m/sec2

c)      144π2m/sec2           (d)     288π2m/sec2   

Subtopic:  Simple Harmonic Motion |
 88%
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A particle moving along the x-axis executes simple harmonic motion, then the force acting on it is given by

(1)   – A Kx           

(2)   A cos (Kx)

(3)   A exp (– Kx

(4)   A Kx

Subtopic:  Simple Harmonic Motion |
 84%
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What is the maximum acceleration of the particle doing the SHM y=2sinπt2+ϕ where 2 is in cm

(a)  π2cm/s2                 (b)    π22cm/s2

(c)    π4cm/s2               (d)    π4cm/s2

Subtopic:  Simple Harmonic Motion |
 92%
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A particle executes simple harmonic motion along a straight line with an amplitude A. The potential energy is maximum when the displacement is

(1)     ±A          

(2)    Zero

(3)     ±A2         

(4)   ±A2

Subtopic:  Energy of SHM |
 81%
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The potential energy of a particle with displacement X depends as U(X). The motion is simple harmonic, when (K is a positive constant)

(1) U=KX22                 

(2) U=KX2   

(3)  U=K                       

(4) U=KX 

Subtopic:  Energy of SHM |
 81%
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The angular velocity and the amplitude of a simple pendulum is ω and a respectively. At a displacement X from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to V is 

(1)     X2ω2a2-X2ω2       

(2)    X2/a2-x2

(3)   a2-X2ω2/X2ω2       

(4)   (a2-x2)/X2

Subtopic:  Energy of SHM |
 78%
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A particle is executing simple harmonic motion with frequency f. The frequency at which its kinetic energy changes into potential energy, will be:

1.   f/2         

2.  f

3.   2 f        

4.  4 f

Subtopic:  Energy of SHM |
 60%
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There is a body having mass m and performing S.H.M. with amplitude a. There is a restoring force ,F=-Kx where x is the displacement. The total energy of body depends upon -

(1)   K, x         

(2)  K, a

(3)   K, a, x    

(4)  K, a, v

Subtopic:  Energy of SHM |
 71%
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The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy)

(1)    18E       

(2)        14E

(3)    12E       

(4)        23E

Subtopic:  Energy of SHM |
 79%
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