A point P lies on the axis of a ring of mass M and radius a at a distance a from its centre C. A small particle starts from P and reaches C under gravitational attraction. Its speed at C will be:
1. √2GMa
2. √2GMa(1−1√2)
3. √2GMa(√2−1)
4. zero
A body of super dense material with mass twice the mass of the earth but size very small compared to size of the earth starts from rest from h<<R above the Earth's surface. It reaches earth in time t:
1. t=√hg
2. t=√2hg
3. t=√2h3g
4. t=√4h3g
Kepler's second law regarding constancy of the areal velocity of a planet is a consequence of the law of conservation of:
1. Energy
2. Linear momentum
3. Angular momentum
4. Mass
A projectile fired vertically upwards with a speed v escapes from the earth. If it is to be fired at 45° to the horizontal, what should be its speed so that it escapes from the earth?
1. v
2. v√2
3. √2v
4. 2v
Magnitude of potential energy (U) and time period (T) of a satellite are related to each other as:
1. T2∝1U3
2. T∝1U3
3. T2∝U3
4. T2∝1U2
Two bodies of masses m and 4m are placed at a distance r. The gravitational potential at a point on the line joining them where the gravitational field is zero is
1. -5Gmr
2. -6Gmr
3. -9Gmr
4. 0
If A is the areal velocity of a planet of mass M, then its angular momentum is:
1. | MA | 2. | 2MA |
3. | A2M | 4. | AM2 |
In planetary motion, the areal velocity of the position vector of a planet depends on the angular velocity (ω) and the distance of the planet from the sun (r). The correct relation for areal velocity is:
1. dAdt∝ωr
2. dAdt∝ω2r
3. dAdt∝ωr2
4. dAdt∝√ωr
A projectile is fired upwards from the surface of the earth with a velocity kve where ve is the escape velocity and k<1. If r is the maximum distance from the center of the earth to which it rises and R is the radius of the earth, then r equals:
1. Rk2
2. R1−k2
3. 2R1−k2
4. 2R1+k2
A satellite is moving very close to a planet of density ρ. The time period of the satellite is:
1. \sqrt{\frac{3 \pi}{ρG}}
2. \left(\frac{3 \pi}{ρG}\right)^{3 / 2}
3. \sqrt{\frac{3 \pi}{2 ρG}}
4. \left(\frac{3 \pi}{2 ρG}\right)^{3 / 2}