Ncert Exercises & Solutions

The structure of ‘A’ and type of isomerism in the above reaction are respectively:

1.	Prop-1-en-2-ol, metamerism
2.	Prop-1-en-1-ol, tautomerism
3.	Prop-2-en-2-ol, geometrical isomerism
4.	Prop-1-en-2-ol, tautomerism

Hint: Oxymercuration-Demercuration reaction

The chemical reaction is as follows:

${CH}_{3} - C \equiv CH \to_{1 % {HgSO}_{4}}^{40 % H_{2} {SO}_{4}} {CH}_{3} - \overset{OH}{C}$
$| = \overset{H}{C}$
$| H \to_{Prop - 1 - en - 2 - ol}^{keto - enol tautomerism} {CH}_{3} - \overset{O}{C}$
$| | - {CH}_{3}$
$Propyne Acetone$

[A] is prop-1-en-2-ol, which undergo tautomerism to form acetone.

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