Ncert Exercises & Solutions

Which of the follwing options are correct for ${[F e {(C N)}_{6}]}^{3 -}$ is

a. $d^{2} s p^{3}$ hybridisation

b. $d^{2} s p^{2}$ hybridisation

c. Paramagnetic

d. Diamagnetic

Choose the correct option
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)

According to VBT, the molecular orbital electronic configuratio of Fe

^{3 -} i n {[F e {(C N)}_{6}]}^{3 -}

Huybridisation = $d^{2} s p^{3}$

Number of unpaired electron =1

Hence, correct choices are options (a) and (c).