Ncert Exercises & Solutions

When 1 mole of ${CrCl}_{3} .6 H_{2} O$ is treated with excess of ${AgNO}_{3},$ 3 moles of $AgCl$ are obtained. The formula of the complex is:

1. [CrCl₃(H₂O)₃].3H₂O
2. [CrCl₂(H₂O)₄]Cl.2H₂O
3. [CrCl₃(H₂O)₅]Cl₂.H₂O
4. [Cr(H₂O)₆]Cl₃