\(E_{Zn/Zn^{+2}}^{o} = 0.76 V \\
E_{Ag^{+}/Ag}^{o}= 0.80 V \)
\(E_{cell}^{o}=E_{Zn/Zn^{2+}}^{o}+E_{Ag^{+}/Ag}^{o}\) \(E_{cell}^{o}=0.76+0.80\) \(E_{cell}^{o}\)= 1.56 V
Step 2:
Calculate the value of \(\Delta_{r} G^{o}\) is as follows: \(\Delta_{r} G^{o} =-nFE_{cell} ^{o}\) \(= -2\times 96487\times 1.56\)
=-301,039.4 J/mol
=-301.01 kJ/mol
