Ncert Exercises & Solutions

Question 12.36:
In the organic compound CH $_{2}$ =CH–CH $_{2}$ –CH $_{2}$ –C≡CH, the pair of hydridised orbitals involved
in the formation of: C $_{2}$ – C $_{3}$ bond is:
(a) sp – sp $^{2}$ (b) sp – sp $^{3}$ (c) sp $^{2}$ – sp $^{3}$ (d) sp $^{3}$ – sp $^{3}$

C \overset{6}{H_{2}} = \overset{5}{C} H - C {\overset{4}{H}}_{2} - C {\overset{3}{H}}_{2} - \overset{2}{C} = \overset{3}{C}

In the given organic compound, the carbon atoms numbered as 1, 2, 3, 4, 5, and 6 are
sp, sp, sp

^{3}

, sp

^{3}

, sp

^{2}

, and sp

^{2}

hybridized respectively. Thus, the pair of hybridized orbitals
involved in the formation of C

_{2}

-C

_{3}

bond is sp – sp

^{3}

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