Question 12.35 In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.
Total mass of organic compound = 0.468 g [Given] Mass of barium sulphate formed = 0.668 g [Given] 1 mol of BaSO = 233 g of BaSO = 32 g of sulphur Thus, 0.668 g of BaSO contains of sulphur = 0.0917 g of sulphur Therefore, percentage of sulphur = 19.59 % Hence, the percentage of sulphur in the given compound is 19.59 %.
