Ncert Exercises & Solutions

When $B C l_{3}$ is treated with water, it hydrolysis and forms $[B {(O H)}_{4}]^{-}$ on whereas $A l C l_{3}$ in acidified aqueous solution forms $[A l {(H_{2} O)}_{6}]^{3 +}$ ion. Explain what is the hybridisation or boron and aluminium in these species ?

In trivalent state, most of the compounds being covalent are hydrolysed in water, e.g., BC on hydrolysis in water form

{[B {(OH)}_{4}]}^{-}

species, the hybridisation state of B is sp³.

BCl + 3 H_{2} O \to B {(OH)}_{3} + 3 HCl

B {(OH)}_{3} + H_{2} O \to {[B {(OH)}_{4}]}^{-} + H^{+}

AlCl₃ in acidified aqueous solution form octahedral

{[Al {(H_{2} O)}_{6}]}^{3 +}

ion. In this complex, the 3d orbitals of Al are involved and the hybridisation state of Al is sp³d².

{AlCl}_{3} + H_{2} O \overset{HCl}{\to} {[Al {(H_{2} O)}_{6}]}^{3 +} + 3 {Cl}^{-} (aq)

NEET Information

courses

Company

Botany Questions

Chemistry Questions

Physics Questions

Zoology Questions