Match the standard free energy of the reaction with the corresponding equilibrium constant.

A. G>0 1. K>1
B. G<0 2. K=1
C. G=0 3. K=0
4. K<1

Codes

A B C
1. 4 1 2
2. 1 2 3
3. 2 4 3
4. 4 1 3
Hint: G=-RT ln K
As we know that, G=-RT ln K 
A. If G>0i.e., G° is positive, then ln K is negative i.e., K<1
B. If G<0, i.e., G° is negative then ln K is positive i.e., K>1
C. If G=0, ln K=0, i.e., K=1.