Ncert Exercises & Solutions

The hybridization of nitrogen in ${NO}_{2}^{+},$ ${NO}_{3}^{-}$ and ${NH}_{4}^{+}$ respectively is :

1. sp, sp^3, and sp²

2. sp, sp^2, and sp³

3. sp², sp, and sp³

4. sp², sp^3, and sp

HINT: Find the sum of lone pair and bond pair.

Explanation:

The type of hybrid orbitals of nitrogen can be decided by using VSEPR theory counting bp and as lp in

{NO}_{2}^{+} = 2

bp + 0

lp

\Rightarrow

sp hybridized.

{NO}_{3}^{-} = 3

bp + 0

lp \Rightarrow

sp² hybridized.

{NH}_{4}^{+} =

4 bp + 0

lp \Rightarrow

sp³ hybridized.