Ncert Exercises & Solutions

Match species are given in Column I with the electronic configuration given in Column II.

Codes

Hint: Electronic configuration of Cr is

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}

A. $Cr (Z = 24) = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1} = [Ar] 3 d^{5} 4 s^{1}$

B. ${Fe}^{2 +} (Z = 26) = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{6} 4 s^{0} = [Ar] 3 d^{6} 4 s^{0}$

C. ${Ni}^{2 +} (Z = 28) = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{8} 4 s^{0} = [Ar] 3 d^{8} 4 s^{0}$

D. $Cu (Z = 29) = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{1} = [Ar] 3 d^{10} 4 s^{1}$