Ncert Exercises & Solutions

Match the following species with their corresponding ground state electronic configuration.

Hint:

Cu

(Z = 29)

:

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{1}

The electronic configuration of the given atom or ions are as follows:

A. $Cu$ $(Z = 29)$ $:$ $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{1}$

B. ${Cu}^{2 +}$ $(Z = 29)$ $:$ $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{9}$

C. ${Zn}^{2 +}$ $(Z = 30)$ $:$ $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10}$

D. ${Cr}^{3 +}$ $(Z = 24)$ $:$ $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{3}$