Ncert Exercises & Solutions

Q 1.10) An electric dipole with dipole moment is aligned at 30° with the direction of a uniform electric field of magnitude $5 \times 10^{4} N C^{- 1}$ . Calculate the magnitude of the torque acting on the dipole.

Electric dipole moment,

p = 4 \times 10^{- 9} C m

Angle made by p with a uniform electric field,

θ = 30 °

Electric field,

E = 5 \times 10^{4} N C^{- 1}

Torque acting on the dipole is given by the relation,

τ = p E \sin θ

= 4 \times 10^{- 9} \times 5 \times 10^{4} \times \sin 30 = 20 \times 10^{- 5} \times \frac{1}{2} = 10^{- 4} Nm

Therefore, the magnitude of the torque acting on the dipole is 10^-4Nm.

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