12.4 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
Hint: The energy of the radiation equals the difference in energy levels.
Step 1: Relate energy with the frequency.
Separation of two energy levels in an atom,
Let \(\nu\) be the frequency of radiation emitted when the atom transits from the upper level to the lower level.
We have the relation for energy as: E =\(h\nu\)
where, h = plank's constant =
Step 2: Find the frequency of the radiation. \(\nu=\frac{E}{h}=\frac{3.68 \times 10^{-19}}{6.62 \times 10^{-32}}=5.55 \times 10^{14} \mathrm{~Hz}\)
Hence, the frequency of the radiation is
