Consider the diffraction pattern for a small pinhole. As the size of the hole is increased:
(a) the size decreases
(b) the intensity increases
(c) the size increases
(d) the intensity decreases
1. (a, b)
2. (a, c)
3. (b, d)
4. (c, d)
(a, b) Hint: The size and intensity of the image depend on the size of the hole.
Step 1: Find the change in size.
(1) When 'a' decreases, 'w' increases.
So, size decreases.
Step 2: Find the change in intensity.
(2) Now, light energy is distributed over a small area and intensity. As the area is area decreasing, so intensity increases.
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