Explanation: For household supplies, AC currents are used which have zero average value over a cycle.
The line that draws the power supply to our house from the street supplies alternating current, whose average value/mean value over a cycle is zero. As the line has some resistance, \((R≠0),\) therefore, voltage and current differ in phase \(ϕ\) such that \(|ϕ|<π/2. \)
The line has some resistance so the power factor; \( \cos \phi=\frac{R}{Z} \neq 0 \) \(\phi \neq \pi / 2 \Rightarrow \phi<\pi / 2\)
therefore, the phase lies between \(0\) and \(\pi/2.\)
Hence, option (2) is the correct answer.
