Which of the following is the most correct electron displacement for a nucleophilic reaction to take place? 

1.
2.
3.
4.

Some meta-directing substituents in aromatic substitution are given. Which one is most deactivating?

1. –SO₃H

2. –COOH

3. –NO₂

4. –C≡N

Among the following compounds the one that is most reactive towards electrophilic nitration is:
1. Benzoic acid
2. Nitrobenzene
3. Toluene
4. Benzene

Among cyclohexanol (I), acetic acid (II), 2, 4, 6-trinitrophenol (III) and phenol (IV) the correct order of decreasing acidic character will be:

Which one is most reactive towards S_N1 reaction?

1. $C_6{H}_{5}CH\left(C_6{H}_5\right)Br$

2. $C_6{H}_{5}CH\left(C{H}_3\right)Br$

3. $C_6{H}_{5}C\left(C{H}_3\right)\left(C_6{H}_5\right)Br$

4. $C_6{H}_{5}C{H}_{2}Br$

Following is the list of some aromatic compounds. Select the correct sequence of decreasing order of reactivity for electrophilic aromatic substitution reaction using the answer codes given below:

a. ${\mathrm{C}}_6{\mathrm{H}}_5 - \mathrm{OH}$

b. ${\mathrm{C}}_6{\mathrm{H}}_5 - {\mathrm{CH}}_3$

c. ${\mathrm{C}}_6{\mathrm{H}}_5 - {\mathrm{NO}}_2$

d. ${\mathrm{C}}_6{\mathrm{H}}_5 - \mathrm{CHO}$

Answer codes :

1. a d b c

2. c d b a 

3. a b d c

4. a b c d

Arrange the decreasing order of reactivity of these compounds for nucleophilic substitution reaction.

a. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{O}-\underset{\underset{\mathrm{O}}{\left|\right|}}{\overset{\stackrel{\mathrm{O}}{\left|\right|}}{\mathrm{S}}}-{\mathrm{CF}}_3$

b. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{O}-\mathrm{TsCl}$

c. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{Cl}$

d. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{Br}$

Select the correct answer from the codes given below:

Codes:

1. c, d, a, b

2. c, d, b, a

3. a, b, c, d

4. a, b, d, c

Arrange decreasing order of reactivity of given compounds with NBS/ ${\mathrm{CCl}}_4$/ hv:

a. ${\mathrm{C}}_6{\mathrm{H}}_5-{\mathrm{CH}}_3$

b. ${\mathrm{C}}_6{\mathrm{H}}_5-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_3$

c. ${\mathrm{C}}_6{\mathrm{H}}_5-{\mathrm{CH}}_2-\mathrm{CH}={\mathrm{CH}}_2$

d. ${\mathrm{C}}_6{\mathrm{H}}_5-\underset{\underset{{\mathrm{CH}}_3}{|}}{\mathrm{C}}\mathrm{H}-\mathrm{CH}={\mathrm{CH}}_2$

Select the correct answer from the codes given below:

Codes :

1. d c a b

2. d c b a 

3. a b c d

4. a c b d