Q. No.Identify the possible link "A" in the following food chain :
Plant → insect - frog → "A" → Eagle
1. Rabbit
2. WoIf
3. Cobra
4. Parrot
Plant → insect - frog → "A" → Eagle
1. Rabbit
2. WoIf
3. Cobra
4. Parrot
Given below is an imaginary pyramid of numbers. What could be one of the possibilities about certain organisms at some of the different levels?
| 1. | Level PC is "insects" and level SC is "small insectivorous birds". |
| 2. | Level PP is "phytoplanktons" in sea and "Whale" on top level TC |
| 3. | Level PP is "pipal trees" and level SC is "sheep". |
| 4. | Level PC is "rats" and level SC is "cats". |
Which one of the following is not a functional unit of an ecosystem
1. Energy flow
2. Decomposition
3. Productivity
4. Stratification
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Identify the likely organisms (a), (b), (c) and (d) in the food web shown below:
Options
|
(a) |
(b) |
(c) |
(d) |
|
|
1. |
deer |
rabbit |
frog |
rat |
|
2. |
dog |
squirrel |
bat |
deer |
|
3. |
rat |
dog |
tortoise |
crow |
|
4. |
squirrel |
cat |
rat |
pigeon |
The rate of formation of new organic matter by rabbits in grassland is called:
| 1. | Net productivity | 2. | Secondary productivity |
| 3. | Net primary productivity | 4. | Gross primary productivity |
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The second stage of hydrosere is occupied by plants like :
1. Azolla
2.Typha
3.Salix
4. Vallisneria
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Secondary productivity is rate of formation of new organic matter by:
1. Parasite
2. Consumer
3. Decomposer
4. Producer
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If 20 J of energy is trapped at producer level, then how much energy will be available to peacock as food in the following chain?
plant → mice → snake → peacock
1. 0.02 J
2. 0.002 J
3. 0.2 J
4. 0.0002 J
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