The correct statement for an ideal gas equation is -

1. n is the number of molecules of a gas.

2. V denotes the volume of 1 mole of the gas.

3. n moles of a gas has a volume V.

4. p is the pressure of the gas when only one mole of the gas is present.

The gas among the following that can be most steadily liquefied is -

1. NH₃                           

2. Cl₂

3. SO₂                           

4. CO₂

Internal energy and pressure of a gas per unit volume are related as                       

1. p= $\frac{2}{3}$E                         

2. p = $\frac{3}{2}$E

3. p=$\frac{1}{2}$E                         

4. p = 2E

If a gas expands at constant temperature, it indicates that                                     

1. kinetic energy of molecules decreases

2. pressure of the gas increases

3. kinetic energy of molecules remains the same

4. number of the molecules of gas increases

The condition of SATP refers to:

1. 25 $°$C and 2 atm             

2. 25 $°$C  and 1 atm

3. 0 $°$C  and 2 atm             

4. 25 $°$C  and 1 bar

While He is allowed to expand through a small jet under adiabatic condition heating effect is observed. This is due to the fact that:

1. helium is an inert gas

2. helium is a noble gas

3. helium is an ideal gas

4. the inversion temperature of helium is very low

The ratio among most probable velocity, mean velocity, and root mean square velocity is given by

1. 1:2:3                           

2. 1: $\sqrt{2}:\sqrt{3}$

3. $\sqrt{2}:\sqrt{3}:\sqrt{\frac{8}{\pi }}$               

4. $\sqrt{2}:\sqrt{\frac{8}{\pi }}:\sqrt{3}$

The condition that favour a pure sample of an ideal gas to have pressure of 1 atm and a concentration of

1 mol L^-1  is -

(R=0.082 L atm mol^-1K^-1)                                     

1. At STP

2. When V = 22.4 L

3. When T = 12 K

4. Impossible under any conditions

The compressibility of a gas is less than unity at STP. Therefore:

1. V_m > 22.4 litre                           

2. V_m < 22.4 litre

3. V_m = 22.4 litre                           

4. V_m = 44.8 litre

The numerical value of c_p -c_v is equal to:

1. R             

2. R/M

3. M/R         

4. None of the above