An absorption line of the lowest frequency in the transition of hydrogen spectra is

1. n=1 to n=2

2. n=3 to n=8

3. n=2 to n=1

4. n=8 to n=3

If uncertainty in the position of an electron is zero the uncertainty in its momentum will be: 

1. <h/4$\mathrm{\pi }$

2. >h/4$\mathrm{\pi }$

3. zero

4. infinite

The maximum number of atomic orbitals associated with a principal quantum number 5 is-

1. 9

2. 12

3. 16

4. 25

The de Broglie wavelength of electron of He⁺ ion is 3.329Å. If the photon emitted upon de-excitation of this He⁺ ion is made to hit H atom in its ground state so as to liberate electron from it, what will be the de Broglie's wavelength of photoelectron ?

1. 0.1518 Å

2. 6.1518 Å

3. 2.3518 Å

4. 4.1218 Å

Velocity of helium atom at 300 K is 2.40 x 10² meter per sec. What is its wavelength? (mass number of helium is 4) -

1. 0.416 nm

2. 0.83 nm

3. 803 Å

4. 8000 Å

The de-Broglie wavelength of a particle having the momentum of
3.3 x 10^-24 kg m s^-1 will be;

1. 0.002 Å

2. 0.02 Å

3. 0.2 Å

4. 2Å

Which of the following statements is not true with respect to photoelectric effect -

1. The plot of kinetic energy of the photoelectrons against frequency of absorbed radiation gives a straight line parallel to x-axis

2. The plot of K.E. of the photoelectrons against frequency of absorbed radiation gives a straight line with slope equal to h and intercept to work function of metal

3. The plot of kinetic energy of the photoelectrons versus the intensity of incident radiation with constant frequency gives a straight line parallel to x-axis

4. When intensity of light is increased the number of photons ejected increases but the energies of these electrons are the same.

The first line in the Lyman series in the spectrum of hydrogen atom occurs at a wavelength of 1215 Å and the limit for Balmer series is 3645 Å. Calculate the wavelength corresponding to series limit of Lyman series.

1. 911.2 Å

2. 812.2 Å

3. 712.2 Å

4. 678.4 Å

The correct order of increasing energy of atomic orbital is: 

1. 3s, 3p, 4s, 3d, 4p

2. 3s, 3p, 3d, 4s, 4p

3. 3s, 3p, 4s, 4p, 3d

4. 3s, 3p, 3d, 4p, 4s

In Rutherford's alpha scattering experiment using gold foil, the kinetic energy of the alpha particle was 1.2 x 10^-12J. For a head on collision, using the formula K.E. = $\frac{1}{4{\mathrm{\pi \epsilon }}_0}$x 2Ze²/r₀ , what may be the magnitude of r₀ [ The nuclear radius of gold, Z=79; $\frac{1}{4{\mathrm{\pi \epsilon }}_0}$= 9 x 10⁹ new-ton/meter² coulomb^-2, e= 1.6x10^-19 coulomb]

1. 3 x 10^-14m

2. 1.3 x 10^-14m

3. 2.1 x 10^-14m

4. 4.3 x 10^-14m