Q. No.Two blocks of masses \(m,2m;\) moving in opposite directions with speed \(u,v\) – undergo a collision. After the collision, the ratio of their speeds remains unchanged. Then, \({\Large\frac uv}=\)
1.
\(1\)
2.
\({\dfrac 12}\)
3.
\(\dfrac 21\)
4.
\(\dfrac 41\)
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1. \(\sqrt{gL} \)
2. \(\sqrt{\sqrt3gL} \)
3. \(\sqrt{2gL\bigg(1-{\large\frac{\sqrt3}{2}}\bigg)} \)
4. \(\sqrt{2gL/\sqrt3} \)
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1. \(20~\text J\)
2. \(40~\text J\)
3. \(30~\text J\)
4. zero
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| 1. | \(mg\sqrt{gL}\) | 2. | \(\Large\frac{mg\sqrt{gL}}{2}\) |
| 3. | \(\Large\frac{mg\sqrt{gL}}{4}\) | 4. | \(\Large\frac{mg\sqrt{gL}}{2\sqrt2}\) |
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(assume that the ball rebounds off a vertical surface and that the effect of gravity is negligible)
1. zero
2. \(50~\text{km/h}\)
3. \(100~\text{km/h}\)
4. \(150~\text{km/h}\)
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1. \(mgu\)
2. \({\Large\frac{3}{4}}mgu \)
3. \({\Large\frac{1}{2}}mgu \)
4. \({\Large\frac{1}{4}}mgu\)
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1. \(W_N=0,W_g>0\)
2. \(W_N>0,W_g=0\)
3. \(W_N=W_g=0\)
4. \(W_N+W_g=0\)
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| Assertion (A): | In a swinging simple pendulum, the power delivered by gravity is maximum when the pendulum is at the lowest point. |
| Reason (R): | The speed of the pendulum bob is highest when it reaches the lowest point and the power is given by \((\vec F.\vec v).\) |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
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The velocity of the first block, after the collision, is:
| 1. | \({\Large\frac12}~\text{m/s}\) | 2. | \(1~\text{m/s}\) |
| 3. | \(2~\text{m/s}\) | 4. | \(0~\text{m/s}\) |
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The momentum of the system, as a result of the collision:
1. increases
2. decreases
3. remains constant
4. decreases suddenly and then increases
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