In following reaction, find out X and Y.

$\mathrm{In} \mathrm{the} \mathrm{reaction},$
$\mathrm{H}-\mathrm{C}\equiv \mathrm{C}-\mathrm{H} \underset{\left(\mathrm{ii}\right){\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Br}}{\overset{\left(\mathrm{I}\right){\mathrm{NaNH}}_2/\mathrm{liq}.{\mathrm{NH}}_3}{\to }}\mathrm{X}$
$\mathrm{X}\underset{\left(\mathrm{ii}\right){\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Br}}{\overset{\left(\mathrm{i}\right){\mathrm{NaNH}}_2/\mathrm{liq}.{\mathrm{NH}}_3}{\to }}{\mathrm{Y}}_{}^{}$

1. X=2-butyne ; Y=3-hexyne

2. X=2-butyne ; Y=2-hexyne

3. X=1-butyne ; Y=2-hexyne

4. X=1-butyne ; Y=3-hexyne

An organic compound X having molecular formula C₅H₁₀O yields phenyl hydrazone and

gives negative response to the iodoform test and Tollen's test. It produces n-pentane on

reduction. X could be

1. pentenal

2. 2-pentanone

3. 3-pentanone

4. n-amyl alcohol

Which of the following will not be soluble in sodium hydrogen carbonate?

1. 2, 4,6 - trinitrophenol

2. benzoic acid

3. o-nitrophenol

4. Benzenesulphonic acid

In a reaction,

A is 

1. HgSO₄/H₂SO₄

2. Cu₂Cl₂

3. H₃PO₂ and H₂O

4. H⁺/H₂O

In the following sequence of reactions,

 CH₃-Br $\stackrel{\mathrm{KCN}}{\to }$A$\stackrel{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }$B$\underset{\mathrm{ether}}{\overset{{\mathrm{LiAlH}}_4}{\to }}$C

the end product C is

1. acetone

2. methane

3. acetaldehyde

4. ethyl alcohol

CH₃CHO and C₆H₅CH₂CHO can be distinguished chemically by

1. Benedict test

2. iodoform test

3. tollen's reagent test

4. Fehling solution test

In a set of reactions, m-bromobenzoic acid gave a product D. Identify the product D.

$\stackrel{{\mathrm{SOCl}}_2}{\to }$B$\stackrel{{\mathrm{NH}}_3}{\to }$C$\underset{{\mathrm{Br}}_2}{\overset{\mathrm{NaOH}}{\to }}\mathrm{D}$

1. 

2. 

3. 

4. 

What is the product obtained in the following reaction?

Which one is a nucleophilic substitution reaction among the following?

1. $R\mathrm{CHO} + R\text{'}\mathrm{MgX}\to R-\underset{\underset{\mathrm{OH}}{\mathrm{I}}}{\mathrm{CH}-R\text{'}}$

2. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\stackrel{{\mathrm{CH}}_3}{\stackrel{\mathrm{I}}{\mathrm{CH}-{\mathrm{CH}}_2\mathrm{Br}}}+{\mathrm{NH}}_3\to {\mathrm{CH}}_3-{\mathrm{CH}}_2-\stackrel{{\mathrm{CH}}_3}{\stackrel{\mathrm{I}}{\mathrm{CH}}-}{\mathrm{CH}}_2{\mathrm{NH}}_2$
$$

3. ${\mathrm{CH}}_3\mathrm{CHO}+\mathrm{HCN}\to {\mathrm{CH}}_3\mathrm{CH}\left(\mathrm{OH}\right)\mathrm{CN}$

4. ${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2+{\mathrm{H}}_2\mathrm{O}\stackrel{{\mathrm{H}}^{+}}{\to } {\mathrm{CH}}_3-\underset{\underset{\mathrm{OH}}{|}}{\mathrm{C}}\mathrm{H}-{\mathrm{CH}}_3$

The reaction of toluene with Cl₂ in presence of FeCl₃ gives 'X' and reaction in presence of

light gives 'Y'. Thus, 'X' and 'Y' are

1. X = Benzal chloride, Y = o-chlorotoluene

2. X = m-chlorotoluene, Y= p-chlorotoluene

3. X = o-and p-chlorotoluene, Y=trichloromethyl benzene

4. X = Benzyl chloride, Y = m-chlorotoluene