Q. No.A high velocity projectile just pierces \(4\) steel plates of identical thickness, setup back-to-back; the projectile being incident normally onto the plates. If the projectile is incident at an angle of \(60^\circ\) with its original direction, the number of plates required to just stop it will be:
1. \(1\)
2. \(2\)
3. \(6\)
4. \(8\)
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The time \((t),\) when the balls collide with each other for the first time, is:
1. \(1~\text s\)
2. \(1.5~\text s\)
3. \(2~\text s\)
4. \(3~\text s\)
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The two balls \((A~\&~B)\) collide with the walls at time \((t)\):
1. \(1.5~\text s,3~\text s\)
2. \(3~\text s,6~\text s\)
3. \(6~\text s,3~\text s\)
4. \(6~\text s,6~\text s\)
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The time interval between the first collision and the second collision between the balls is:
1. \(6~\text{s}\)
2. \(3~\text{s}\)
3. \(4.5~\text{s}\)
4. \(4~\text{s}\)
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The work done by the force \(F\) equals:
1. \(\dfrac{Fd}{2}\)
2. \(Fd\)
3. \(2Fd\)
4. \(\dfrac{Fd}{3}\)
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The potential energy stored in the spring equals:
| 1. | \(\Large\frac{Fd}{2}\) | 2. | \(Fd\) |
| 3. | \(\Large\frac{2Fd}{3}\) | 4. | \(\Large\frac{Fd}{3}\) |
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The force exerted by the spring equals:
1. \(F\)
2. \(\Large\frac F2\)
3. \(2F\)
4. \(\sqrt2F\)
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| 1. | \(\sqrt{gL}\) | 2. | \(\sqrt{\Large\frac{gL}{2}}\) |
| 3. | \(\sqrt{2gL}\) | 4. | \(\sqrt{\Large\frac{5gL}{2}}\) |
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| Assertion (A): | Work done by all forces, conservative or non-conservative, equals the change in the total energy of the system. |
| Reason (R): | According to Newton's laws of motion, the acceleration of any particle of the system is due to all forces acting on it; and therefore the work done on it by these is the total work done. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
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| 1. | \(\dfrac{1}{2}\) | 2. | \(\dfrac{1}{3}\) |
| 3. | \(\dfrac{1}{9}\) | 4. | \(\dfrac{1}{\sqrt3}\) |
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