The potential difference across the 100Ω resistance in the following circuit is measured by a voltmeter of 900 Ω resistance. The percentage error made in reading the potential difference is :
(1)
(2) 0.1
(3) 1.0
(4) 10.0
A galvanometer with a resistance of 36 Ω is changed into an ammeter by using a shunt of 4 Ω. The fraction f0 of total current passing through the galvanometer will be:
1.
2.
3.
4.
If the ammeter in the given circuit reads 2 A, the resistance R is :
(1) 1 ohm
(2) 2 ohm
(3) 3 ohm
(4) 4 ohm
Two resistances of 400 Ω and 800 Ω are connected in series with a 6-volt battery of negligible internal resistance. A voltmeter of resistance 10,000 Ω is used to measure the potential difference across 400 Ω. The error in the measurement of potential difference in volts approximately is :
(1) 0.01
(2) 0.02
(3) 0.03
(4) 0.05
A galvanometer, having a resistance of 50 Ω gives a full scale deflection for a current of 0.05 A. The length in meter of a resistance wire of area of cross-section 2.97× 10–2 cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (Specific resistance of the wire = 5 × 10–7 Ωm)
(1) 9
(2) 6
(3) 3
(4) 1.5
An ammeter reads up to 1 ampere. Its internal resistance is 0.81 ohm. To increase the range to 10 A the value of the required shunt is :
(1) 0.09 Ω
(2) 0.03 Ω
(3) 0.3 Ω
(4) 0.9 Ω
The length of a wire of a potentiometer is 100 cm, and the emf of its standard cell is E volt. It is employed to measure the e.m.f of a battery whose internal resistance is 0.5 Ω. If the balance point is obtained at l = 30 cm from the positive end, the e.m.f. of the battery is :
(1)
(2)
(3)
(4) , where i is the current in the potentiometer
What is the reading of the voltmeter in the following figure?
(1) 3 V
(2) 2 V
(3) 5 V
(4) 4 V
The current flowing in a coil of resistance 90 Ω is to be reduced by 90%. What value of resistance should be connected in parallel with it
(1) 9 Ω
(2) 90 Ω
(3) 1000 Ω
(4) 10 Ω
In a metre bridge experiment, the null point is obtained at 20 cm from one end of the wire when resistance X is balanced against another resistance Y. If X < Y, then where will be the new position of the null point from the same end, if one decides to balance a resistance of 4X against Y
(1) 50 cm
(2) 80 cm
(3) 40 cm
(4) 70 cm