Mendel’s success was largely due to his choice of the garden pea plant for his experiments. The advantages of using this plant included:

I. Presence of easily observable contrasting traits for many characters.
II. It was possible to control pollination [and hence mating] between different pea plants.
III. A large number of seeds could be produced and statistical analysis was therefore more accurate.
IV. A long generation time means expression of all traits completely.
V. Many observable traits were controlled by single genes.

1. Only I, II and III
2. Only I, II and V
3. Only I, II, III and V
4. Only II, III, IV and V

Subtopic:  Introduction to Genetics: 1 |
 51%
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What was the most significant conclusion that Gregor Mendel drew from his experiments with pea plants?

(1) There is considerable genetic variation in garden peas.

(2) Traits are inherited in discrete units, and are not the results of ʺblending.ʺ

(3) Genes are composed of DNA.

(4) An organism that is homozygous for many recessive traits is at a disadvantage.

Subtopic:  Introduction to Genetics: 2 |
 79%
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An organism with two copies of the same allele is:

(1) Homozygous for that trait

(2) Homologous for the allele

(3) Heterozygous for that trait

(4) Heterologous for the allele

Subtopic:  Monohybrid Cross: 1 |
 75%
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Which of the following about the law of segregation is true?

(1) It states that each of two alleles for a given trait segregate into same gametes.

(2) It can be explained by the segregation of heterologous chromosomes during meiosis.

(3) It can account for the 3:1 ratio seen in the F2 generation of Mendelʹs crosses.

(4) It is a method that can be used to determine the number of chromosomes in a plant.

Subtopic:  Law of Segregation |
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In guinea pigs, black coat color is a dominant trait and white is a recessive trait. When heterozygous black pigs are intercrossed the chance of the first two offspring being black is:

(1) 75 %

(2) 56 %

(3) 44 %

(4) 6 %

Subtopic:  Law of Segregation |
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The minimum progeny population size allowing for random union of all kinds of gametes from AaBbCc parents is:

(1) 9

(2) 16

(3) 27

(4) 64

Subtopic:  Dihybrid Cross Analysis |
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How many unique gametes could be produced through independent assortment by an individual with the genotype AaBbCCDdEE?

(1) 4

(2) 8

(3) 16

(4) 32

Subtopic:  Dihybrid Cross: Details |
 73%
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Two heterozygous round yellow seeded pea plants are intercrossed. In the progeny, the trait for seed shape will segregate in the ratio:

(1) 1 : 1

(2) 3 : 1

(3) 1 : 1 : 1 : 1

(4) 9 : 3 : 3 : 1

Subtopic:  Dihybrid Cross: Details |
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Given the parents AABBCc × AabbCc, assume simple dominance and independent assortment. What proportion of the progeny will be expected to phenotypically resemble the first parent?

(1) 1/4

(2) 1/8

(3) 3/4

(4) 3/8

Subtopic:  Dihybrid Cross: Details |
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In a cross between AABB X aabb, the ratio of F2 genotypes between AABB, AaBB, Aabb and aabb would be:

(1) 9 : 3 : 3 : 1

(2) 2 : 1 : 1 : 2

(3) 1 : 2 : 2 : 1

(4) 7 : 5 : 3 : 1

Subtopic:  Dihybrid Cross: Details |
 52%
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