In the given reaction,

$C{H}_3-C\equiv N \stackrel{H_{2}O/∆}{\to }\left(A\right)\stackrel{H_{2}O/\stackrel{\oplus }{H/∆}}{\to }\left(B\right)$

(A) and (B) respectively are:

(1) $O$
$\parallel$
$C{H}_3-C-N{H}_2 and C{H}_{3}COOH$

(2) $C{H}_{3}COON{H}_4 and C{H}_{3}COOH$

(3) $C{H}_{3}CON{H}_2 and C{H}_{3}COON{H}_4$

(4) $C{H}_3-CH=NH and C{H}_{3}COOH$

Which among the following compounds will give nucleophilic addition reaction?

(1) $O$
$\parallel$
$C_6{H}_5-C-Cl$

(2) $O$
$\parallel$
$C{H}_3-C-N{H}_2$

(3)

(4) $O$
$\parallel$
$C{H}_3-C-O{C}_2{H}_5$

Which among the following reagents can be used for the test of carbonyl group in laboratory?

1. $N{H}_{2}OH$

2. $N{H}_{2}N{H}_2$

3. $NaS{O}_{3}H$

4. $2,4-DNPH$

In the reaction sequence,

[X] will be:

1.		2.	$C{H}_{3}COOH$
3.	$C_6{H}_5-N{H}_2$	4.	$C{H}_3-CO-NH-C_6{H}_5$

Consider the following statements for carbonyl compounds:

(i) They give nucleophilic addition reaction.

(ii) Aldehyde is more reactive than ketone for nucleophilic addition reaction.

(iii) $\beta -$hydrogen of carbonyl compound is more acidic than $\alpha -$hydrogen.

(iv) They give addition reaction followed by elimination reaction with $N{H}_2-NH-C_6{H}_4-C{H}_3$.

Of these statements:

(1) (i) and (ii) are correct

(2) (i), (ii) and (iv) are correct

(3) (i), (ii) and (iii) are correct

(4) (i), (ii), (iii) and (iv) are correct

Consider the following statements for a carbonyl compound:

(i) It gives addition reaction

(ii) It gives condensation reaction

(iii) It gives elimination reaction

(iv) It gives oxidation reaction

Of these statements:

(1) (i), (ii), (iii) and (iv) are correct

(2) (i) and (ii) are correct

(3) (i), (ii) and (iii) are correct

(4) (i), (ii) and (iv) are correct

Which compound will give E1cb reaction?

(1) $C{F}_3-CHC{l}_2$

(2) $C_6{H}_5-C{H}_2-C{H}_2-F$

(3) $N{O}_2$
$l$
$C{H}_3-CH-CH{C}_6{H}_5$
$l$
$OCOC{H}_3$

(4) All of these

Reaction intermediate of E1 reaction is:

(1) Carbocation

(2) carbanion

(3) Carbene

(4) free radical

Reaction intermediate of E1cb reaction is:

1. Carbocation

2. Carbanion

3. benzyne

4. free radical

In the given reaction:

${\mathrm{CH}}_3-{\mathrm{CH}}_2-\underset{{\mathrm{CH}}_3}{\underset{|}{\mathrm{CH}}}-{\mathrm{CH}}_2-\mathrm{Br}\stackrel{\mathrm{alc}.\mathrm{KOH}/∆}{\to }\left[\mathrm{X}\right]$

[X] will be:

(1) $C{H}_3-C{H}_2-C=C{H}_2$
$I$
$C{H}_3$

(2) $C{H}_3-CH=C-C{H}_3$
$l$
$C{H}_3$

(3) $C{H}_2=CH-CH-C{H}_3$
$l$
$C{H}_3$

(4) $C{H}_3-CH=CH-C{H}_2-C{H}_3$