Consider the following reaction.
Cl₂ + H₂ → A
H₂ + Na → B
H₂ + CuO → C  + H₂O

A, B and C in the above mentioned reaction are respectively-

1. A= HCl; B= NaH₂; C= Cu₂O
2. A= HCl; B= NaH; C= Cu₂O
3. A= No reaction; B= NaH; C= Cu
4. A= HCl; B= NaH; C= Cu

The hydrides of N, O and F has the higher boiling points than the hydrides of their subsequent group members because-

1. Lower molecular masses of NH₃, H₂O and HF
2. Strong hydrogen bonding in NH₃, H₂O and HF
3. Strong vanderwall forces in NH₃, H₂O and HF
4. None of the above

Given below are two statements: 

The number of hydrogen-bonded water molecule(s) associated with CuSO₄.5H₂O are-

1. 2
2. 3
3. 1
4. 5

The strength of 10 volume solutions of hydrogen peroxide is-

1. 6%
2. 10%
3. 0.1%
4. 3%