The correct order of increasing electrical conductance is -
1. BeH₂ > CaH₂ > TiH₂
2. BeH₂ < CaH₂ > TiH₂
3. TiH₂ < BeH₂ < CaH₂
4. BeH₂ < CaH₂ < TiH₂

The correct order of increasing reducing nature is -

1. NaH > H₂O < MgH₂

_{2. ${\mathrm{H}}_2\mathrm{O}$ > ${\mathrm{MgH}}_2$> NaH}

_{3. ${\mathrm{H}}_2\mathrm{O}$< ${\mathrm{MgH}}_2$ < NaH}

_{4. ${\mathrm{H}}_2\mathrm{O}$ $\simeq$ ${\mathrm{MgH}}_2$ < NaH}

The isotopes of hydrogen and their mass ratio are -

1. Protium, Deuterium, Tritium ; 3:2:3

2. Protium, Deuterium, Tritium ; 1:2:3

3. Protium, Deuterium, Tritium ; 2:2:3

4. Protium, Deuterium, Tritium ; 3:2:1

Hydrogen exists in diatomic form rather than monoatomic form under normal conditions -

1. Due to high ionization enthalpy

2. Due to low ionization enthalpy

3. Due to high electron gain enthalpy

4. Due to low electron gain enthalpy

The role of an electrolyte in the  preparation of H₂ by electrolytic method is:

The products obtained on the completion of the following reactions (i) and (ii) respectively are :

1. A = CO, and H₂ ; B = Na₂ZnO₂
2. A  = CO₂ ; B = Na₄ZnO₄
3. A = CH₃CH₂CH₂OH ; B=  ZnO
4. None of the above

The consequences of high enthalpy of H–H bond in dihydrogen is /are :

The correct statement about electron-deficient hydride is that it:

The hydrides of carbon (C_nH_{2n + 2}) can act as -

1. Lewis acid.

2. Lewis base.

3. Both 1 and 2

4. None of the above

“Non-stoichiometric hydrides” are :