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Q. No.The mass of CO2 produced by heating 20 g of 20% pure limestone
as per the given below equation is:
\(\left[\mathrm{CaCO}_3 \stackrel{1200 \mathrm{~K}}{\longrightarrow} \mathrm{CaO}+\mathrm{CO}_2\right] \)
as per the given below equation is:
\(\left[\mathrm{CaCO}_3 \stackrel{1200 \mathrm{~K}}{\longrightarrow} \mathrm{CaO}+\mathrm{CO}_2\right] \)
| 1. | 1.32 g | 2. | 1.12 g |
| 3. | 1.76 g | 4. | 2.64 g |
Subtopic: Equation Based Problem |
69%
From NCERT
NEET - 2023
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Select the correct statements from the following:
Choose the correct answer from the option given below:
| A. | Atoms of all elements are composed of two fundamental particles. |
| B. | The mass of the electron is \(9.10939 \times 10^{-31} \mathrm{~kg} \text {. }\). |
| C. | All the isotopes of a given element show same chemical properties. |
| D. | Protons and electrons are collectively known as nucleons. |
| E. | Dalton's atomic theory regarded the atom as an ultimate particle of matter. |
| 1. | B, C and E only | 2. | A, B and C only |
| 3. | C, D and E only | 4. | A and E only |
Subtopic: Introduction |
69%
From NCERT
NEET - 2023
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The density of 1 M solution of a compound 'X' is 1.25 g mL-1. The correct option for the molality of solution is:
(Molar mass of compound X = 85 g):
(Molar mass of compound X = 85 g):
| 1. | 0.705 m | 2. | 1.208 m |
| 3. | 1.165 m | 4. | 0.858 m |
Subtopic: Concentration Based Problem |
65%
From NCERT
NEET - 2023
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What mass of 95% pure CaCO3 will be required to neutralize 50 mL of 0.5 M HCl solution according to the following reaction?
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate upto the second place of decimal point]
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate upto the second place of decimal point]
| 1. | 9.50 g | 2. | 1.25 g |
| 3. | 1.32 g | 4. | 3.65 g |
Subtopic: Equation Based Problem |
51%
From NCERT
NEET - 2022
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Match list-I with list-II:
| List-I | List-II | ||
| (a) | 4.48 litres of O2 at STP | (i) | 0.2 moles |
| (b) | 12.022 × 1022 molecules of H2O | (ii) | 12.044 × 1023 molecules |
| (c) | 96 g of O2 | (iii) | 6.4 g |
| (d) | 88 g of CO2 | (iv) | 67.2 litres at STP |
Choose the correct answer from the options given below:
| (a) | (b) | (c) | (d) | |
| 1. | (i) | (iii) | (iv) | (ii) |
| 2. | (iii) | (i) | (iv) | (ii) |
| 3. | (iv) | (i) | (ii) | (iii) |
| 4. | (iii) | (i) | (ii) | (iv) |
Subtopic: Moles, Atoms & Electrons |
From NCERT
NEET - 2022
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The mass of a 2.5 mL solution (the density of the solution is 2.15 g/mL) in the correct significant figures is:
1. 5375 × 10–3 g
2. 5.4 g
3. 5.38 g
4. 53.75 g
1. 5375 × 10–3 g
2. 5.4 g
3. 5.38 g
4. 53.75 g
Subtopic: Introduction |
70%
From NCERT
NEET - 2022
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An organic compound contains 80 % (by wt.) carbon and the remaining percentage of hydrogen. The empirical formula of this compound is:
[Atomic wt. of C is 12, H is 1]
| 1. | CH3 | 2. | CH4 |
| 3. | CH | 4. | CH2 |
Subtopic: Empirical & Molecular Formula |
70%
From NCERT
NEET - 2021
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The maximum number of atoms is present in which of the following -
1. 1 g of Mg(s)
2. 1 g of O2 (g)
3. 1 g of Li(s)
4. 1 g of Ag(s)
Subtopic: Moles, Atoms & Electrons |
78%
From NCERT
NEET - 2020
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One mole of carbon atom weighs 12 g, the number of atoms in it is equal to, (Mass of carbon – 12 is )
1.
2.
3.
4.
Subtopic: Moles, Atoms & Electrons |
77%
From NCERT
NEET - 2020
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The number of moles of hydrogen molecules required to produce 20 moles of ammonia through Haber's process is -
| 1. | 40 mol | 2. | 10 mol |
| 3. | 20 mol | 4. | 30 mol |
Subtopic: Limiting Reagent | Equation Based Problem |
78%
From NCERT
NEET - 2019
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