Given below are two statements: one is labeled as Assertion (A) and the other is labeled as Reason (R): 
Assertion (A): Helium is used to dilute oxygen in the diving apparatus. 
Reason (R): Helium has a high solubility in O2.
In the light of the above statements choose the correct answer from the options given below:
1. (A) is false but (R) is true.
2. Both (A) and (R) are true and (R) is the correct explanation of (A). 
3. Both (A) and (R) are true and (R) is NOT the correct explanation of (A).
4. (A) is true but (R) is false.
Subtopic:  Concentration Terms & Henry's Law |
From NCERT
NEET - 2023
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Which amongst the following aqueous solution of electrolytes will have minimum elevation in boiling point?
Choose the correct option:-
1. 0.05 M NaCI 2. 0.1 M KCI
3. 0.1 M MgSO4 4. 1 M NaCI
Subtopic:  Van’t Hoff Factor |
 69%
From NCERT
NEET - 2023
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In one molal solution that contains 0.5 mole of a solute, there is:
1. 1000 g of solvent 2. 500 mL of solvent
3. 500 g of solvent 4. 100 mL of solvent
Subtopic:  Concentration Terms & Henry's Law |
 73%
From NCERT
NEET - 2022
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One mole of sugar is dissolved in three moles of water at 298 K. The relative lowering of vapour pressure is:

1. 0.25 2. 0.15
3. 0.50 4. 0.33
Subtopic:  Relative Lowering of Vapour Pressure |
 70%
From NCERT
NEET - 2022
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KH value for some gases at the same temperature 'T' are given:
gas KH/k bar
Ar 40.3
CO2 1.67
HCHO 1.83 × 10-5
CH4 0.413
KH is Henry's Law constant in water. The order of their solubility in water is :
1. Ar < CO2 < CH4 < HCHO 2. Ar < CH4 < CO2 < HCHO
3. HCHO < CO2 < CH4 < Ar 4. HCHO < CH4 < CO2 < Ar
Subtopic:  Concentration Terms & Henry's Law |
 68%
From NCERT
NEET - 2022
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Following solutions were prepared by dissolving 10 g of glucose (C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water (P3). The decreasing order of osmotic pressure of these solutions is:

1. P2 > P3 > P1 2. P3 > P1 > P2
3. P2 > P1 > P3 4. P1 > P2 > P3
Subtopic:  Osmosis & Osmotic Pressure |
 67%
From NCERT
NEET - 2021
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The correct option for the value of vapor pressure of a solution at 45 °C with benzene to octane in a molar ratio 3:2 is:

[At 45 °C vapor pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]
1. 336 mm of Hg
2. 350 mm of Hg
3. 160 mm of Hg
4. 168 mm of Hg

Subtopic:  Raoult's Law |
 70%
From NCERT
NEET - 2021
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The mixture that shows positive deviation from Raoult's law is-

1. Benzene + Toluene

2. Acetone + Chloroform

3. Chloroethane + Bromoethane

4. Ethanol + Acetone

Subtopic:  Raoult's Law |
 66%
From NCERT
NEET - 2020
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The freezing point of depression constant (Kf ) of benzene is 5.12 K kg mol-1. The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is-
(rounded off upto two decimal places):

1. 0.80 K 2. 0.40 K
3. 0.60 K 4. 0.20 K
Subtopic:  Depression of Freezing Point |
 86%
From NCERT
NEET - 2020
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If 8 g of a non-electrolyte solute is dissolved in 114 g of n-octane to reduce its vapor pressure to 80 %, the molar mass (in g mol–1) of the solute is -

[Molar mass of n-octane is 114 g mol–1]

1. 40 2. 60
3. 80 4. 20
Subtopic:  Relative Lowering of Vapour Pressure |
 59%
From NCERT
NEET - 2020
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