A spring stretches by \(2~\text{mm}\) when it is loaded with a mass of \(200~\text{g}.\) From equilibrium position the mass is further pulled down by \(2~\text{mm}\) and released. The frequency associated with the system and maxmimum energy in the spring are __________ \(\text{Hz}\) and _______ \(\text{J},\) respectively.
( Take \(g =10~\text{m/s}^{2}\)
)
1. \(\dfrac{5 \sqrt{50}}{\pi}~\text{and}~8 \times 10^{-3} \)
2. \( \dfrac{5 \sqrt{50}}{\pi}~\text{and}~8 \)
3. \(10 \sqrt{50}~ \text{and}~2 \times 10^{-3} \)
4. \(\dfrac{5 \sqrt{50}}{\pi} ~\text{and}~16 \times 10^{-3}\)
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The frequency of oscillation of mass \(m\) suspended by a spring is \(\nu_1\). If the length of spring is cut to half, the same mass oscillates with frequency \(\nu_2\). The value of \(\nu_2 / \nu_1\) is:
1. \(1\)
2. \(2\)
3. \(\sqrt2\)
4. \(\sqrt3\)
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As shown in the figure, a spring is kept in a stretched position with some extension by holding the masses \(1~\text{kg}\) and \(0.2~\text{kg}\) with a separation more than spring natural length and are released. Assuming the horizontal surface to be frictionless, the angular frequency (in SI unit) of the system is:
            
1. \(30\)
2. \(27\) 
3. \(20\) 
4. \(5\) 
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Two blocks of masses \(m\) and \(M, (M>m), \) are placed on a frictionless table as shown in figure. A massless spring with spring constant \(k\) is attached with the lower block. If the system is slightly displaced and released, then (\(\mu =\) coefficient of friction between the two blocks)
      
\(\mathrm{A.}\) The time period of small oscillation of the two blocks is \(T=2 \pi \sqrt{\dfrac{({m}+{M})}{{k}}}\)
\(\mathrm{B.}\) The acceleration of the blocks is \(a=-\dfrac{k x}{M+m},(x=\)displacement of the blocks from the mean position)
\(\mathrm{C.}\) The magnitude of the frictional force on the upper block is \(\dfrac{m \mu|x|}{M+m}\)
\(\mathrm{D.}\) The maximum amplitude of the upper block, if it does not slip, is \(\dfrac{\mu(M+m) g}{k}\)
\(\mathrm{E.}\) Maximum frictional force can be \(\mu(M+m)g\)
Choose the correct answer from the options given below:
1. \(\mathrm{A, B, C}~\text{Only}\) 2. \(\mathrm{A, B, D}~\text{Only}\)
3. \(\mathrm{C, D, E}~\text{Only}\) 4. \(\mathrm{B, C, D}~\text{Only}\)
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Two bodies \(A\) and \(B\) of equal mass are suspended from two massless springs of spring constant \(k_1\) and \(k_2\), respectively. If the bodies oscillate vertically such that their amplitudes are equal, the ratio of the maximum velocity of \(A\) to the maximum velocity of \(B\) is:
1. \(\dfrac{k_1}{k_2}\)

2. \(\sqrt{\dfrac{k_1}{k_2}} \)

3. \(\sqrt{\dfrac{{k}_2}{{k}_1}} \)

4. \(\dfrac{k_2}{k_1} \)
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A block of mass \(m\) is connected with a spring, and the time period of its oscillation is \({T.}\) If the mass is increased to \({9m}\) while keeping the same spring, the new time period of oscillation will be:
1. \(3T\)

2. \(\dfrac{3}{2}T\)

3. \({5}T\)

4. \(\dfrac{T}{5}\)
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For the oscillations exhibited by the spring-block system, on a smooth surface (along the springs), the time period is:
    
 
1. \(\begin{aligned} {2}\mathit{\pi}\sqrt{\dfrac{{m}\left({{k}_{1}{+}{k}_{2}}\right)}{{k}_{1}{k}_{2}}} & \end{aligned}\) 2. \(\begin{aligned}2\pi\sqrt{{{m\left({k_{1}+k_{2}}\right)}\over{2k_{1}k_{2}}}} &\end{aligned}\)
3. \(\begin{aligned} 2\pi\sqrt{{{m}\over{k_{1}+k_{2}}}} & \end{aligned}\) 4. \(\begin{aligned} \pi\sqrt{{{m}\over{k_{1}+k_{2}}}} & \end{aligned}\)
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A block of mass \(2\) kg is attached to two identical springs, each with a force constant of \(20\) N/m, as shown in the figure. The time period of the oscillation of the block is: 
1. \(2\pi \sqrt{\dfrac{1}{20}}\) s 2. \(\pi \sqrt{\dfrac{1}{20}}\) s
3. \(2\pi \sqrt{\dfrac{1}{10}}\) s 4. \(\pi \sqrt{\dfrac{1}{10}}\) s
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A block of mass \(m\) is connected to two identical springs of force constant \(K\) as shown. The frequency of the block is:
    
1. \({2}\mathit{\pi}\sqrt{\left[{\frac{2m}{K}}\right]}\)
2. \(\frac{1}{{2}\mathit{\pi}}\sqrt{\left[{\frac{K}{m}}\right]}\)
3. \({2}\mathit{\pi}\sqrt{\left[{\frac{m}{2K}}\right]}\)
4. \(\frac{1}{{2}\mathit{\pi}}\sqrt{\left[{\frac{2K}{m}}\right]}\)
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In the shown mass-spring system, when it is set into oscillations along the spring, it has angular frequency \(\omega_1\) if \(m=1\) kg and \(\omega_2\) if \(m=2\) kg. Then the value of \(\dfrac{\omega_1}{\omega_2}\) is equal to:
              
1. \(1\)
2. \(\sqrt{2}\)
3. \(\frac{1}{\sqrt{2}}\)
4. \(2\)
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