The gravitational force between H-atom and another particle of mass m will be given by Newton's law \(F=\frac{GMm}{r^2},\) where r is
in km and

1. M=mproton+melectron.
2. M=mproton+melectron-\(\frac{B}{c^2}\) ( B=13.6 eV ).
3. M is not related to the mass of the hydrogen atom.
4. M=mproton+melectron-\(\frac{|V|}{c^2}\)  ( |V| = magnitude of the potential energy of electron in the H-atom).

Subtopic:  Nuclear Binding Energy |
 67%
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When a nucleus in an atom undergoes a radioactive decay, the electronic energy levels of the atom:
 

1. do not change for any type of radioactivity
2. change for  α  and  β -radioactivity but not for  γ -radioactivity
3. change for  α -radioactivity but not for others
4. change for  β -radioactivity but not for others

Subtopic:  Types of Decay |
 76%
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Tritium is an isotope of hydrogen whose nucleus triton contains 2 neutrons and 1 proton. Free neutrons decay into p+e¯+ν¯. If one of the neutrons in Triton decays, it would transform into He3 nucleus. This does not happen. This is because;
 

1. triton energy is less than that of a Henucleus
2. the electron created in the beta decay process cannot remain in the nucleus
3. both the neutrons in Triton have to decay simultaneously resulting in a nucleus with 3 protons, which is not a Henucleus.
4. free neutrons decay due to external perturbations which is absent in Triton nucleus

Subtopic:  Types of Decay |
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Mx and My denote the atomic masses of the parent and the daughter nuclei respectively in radioactive decay. The Q-value for a β- decay is Q1 and that for a β+ decay is Q2. If me denotes the mass of an electron, then which of the following statements is correct?

1. Q1=(Mx-My) c2 and Q2=[Mx-My-2me]c2

2. Q1=(Mx-My) c2 and Q2=(Mx-My) c2

3. Q1=(Mx-My-2me) c2 and Q2=(Mx-My+2me) c2

4. Q1=(Mx-My+2me) c2 and Q2=(Mx-My+2me)c2

Subtopic:  Nuclear Binding Energy |
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In a nuclear reactor, moderators slow down the neutrons which come out in a fission process. The moderator used have light nuclei. Heavy nuclei will not serve the purpose, because:

1. they will break up
2. elastic collision of neutrons with heavy nuclei will not slow them down
3. the net weight of the reactor would be unbearably high
4. substances with heavy nuclei do not occur in the liquid or gaseous state at room temperature

Subtopic:  Nuclear Energy |
 65%
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Fusion processes, like combining two deuterons to form a \(\mathrm{He}\)-nucleus are impossible at ordinary temperatures and pressure. The reasons for this can be traced to the fact:

(a) nuclear forces have short-range
(b) nuclei are positively charged
(c) the original nuclei must be completely ionized before fusion can take place
(d) the original nuclei must first break up before combining with each other

1. (a, c)
2. (a, d)
3. (b, d)
4. (a, b)

Subtopic:  Nuclear Energy |
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