The volume \(V\) versus temperature \(T\) graph for a certain amount of a perfect gas at two pressures \(P_1\) and
\(P_2\) are shown in the figure.

Here:
| 1. | \({P}_1<{P}_2\) |
| 2. | \({P}_1>{P}_2\) |
| 3. | \({P}_1={P}_2\) |
| 4. | Pressures can’t be related |
We have two vessels of equal volume, one filled with hydrogen and the other with equal mass of helium. The common temperature is \(27^{\circ}\text{C}.\) What is the relative number of molecules in the two vessels?
1. \(\frac{n_\mathrm{H}}{n_\mathrm{He}} = \frac{1}{1}\)
2. \(\frac{n_\mathrm{H}}{n_\mathrm{He}} = \frac{5}{1}\)
3. \(\frac{n_\mathrm{H}}{n_\mathrm{He}} = \frac{2}{1}\)
4. \(\frac{n_\mathrm{H}}{n_\mathrm{He}} = \frac{3}{1}\)
The ratio of is: (symbols have their usual meaning)
At \(10^{\circ}\text{C}\) the value of the density of a fixed mass of an ideal gas divided by its pressure is \(x.\) At \(110^{\circ}\text{C}\) this ratio is:
| 1. | \(x\) | 2. | \(\dfrac{383}{283}x\) |
| 3. | \(\dfrac{10}{110}x\) | 4. | \(\dfrac{283}{383}x\) |
| 1. | \(\dfrac{2}{3}\) | 2. | \(\dfrac{3}{4}\) |
| 3. | \(2\) | 4. | \(\dfrac{1}{2}\) |
The root mean square velocity of the molecules of a gas is \(300 ~\text{m/s}.\) What will be the root mean square speed of the molecules if the atomic weight is doubled and the absolute temperature is halved?
| 1. | \(300 ~\text{m/s}\) | 2. | \(150 ~\text{m/s}\) |
| 3. | \(600 ~\text{m/s}\) | 4. | \(75 ~\text{m/s}\) |
The rms speed of oxygen atoms is v. If the temperature is halved and the oxygen atoms combine to form oxygen molecules, then the rms speed will be:
1.
2.
3. 2v
4.
The figure below shows the graph of pressure and volume of a gas at two temperatures \(T_1\) and \(T_2.\) Which one, of the following, inferences is correct?

| 1. | \(T_1>T_2\) |
| 2. | \(T_1=T_2\) |
| 3. | \(T_1<T_2\) |
| 4. | No inference can be drawn |
An experiment is carried out on a fixed amount of gas at different temperatures and at high pressure such that it deviates from the ideal gas behaviour. The variation of with P is shown in the diagram. The correct variation will correspond to: (Assuming that the gas in consideration is nitrogen)
| 1. | Curve A | 2. | Curve B |
| 3. | Curve C | 4. | Curve D |
The average translational kinetic energy of \(O_2\) (molar mass \(32\)) molecules at a particular temperature is \(0.048~\text{eV}\). The translational kinetic energy of \(N_2\) (molar mass \(28\)) molecules in \(\text{eV}\) at the same temperature is:
1. \(0.0015\)
2. \(0.003\)
3. \(0.048\)
4. \(0.768\)