The rate equation of a reaction is expressed as, Rate = \(k(P_{CH_{3}OCH_{3}})^{\frac{3}{2}}\)
(Unit of rate = bar min-1)
The units of the rate constant will be:
1. bar1/2 min
2. bar2 min-1
3. bar-1min-2
4. bar-1/2min-1
The factor(s) that affect the rate of a chemical reaction is/are:
1. Concentration/Pressure of reactants.
2. Temperature.
3. Presence of a catalyst.
4. All of the above.
The correct statement about the rate constant of a reaction is:
1. | Rate constant is nearly doubled with a rise in temperature by 10 °C |
2. | Rate constant becomes half with a rise in temperature by 10 °C |
3. | Rate constant remains unchanged with a rise in temperature by 10 °C |
4. | None of the above |
t/s | 0 | 30 | 60 | 90 |
[Ester]/mol L-1 | 0.55 | 0.31 | 0.17 | 0.085 |
A reaction is first-order with respect to A and second-order with respect to B. The concentration of B is increased three times. The new rate of the reaction would:
1. | Decrease 9 times | 2. | Increase 9 times |
3. | Increase 6 times | 4. | Decrease 6 times |
In a reaction between A and B, the initial rate of reaction (r0) was measured for different initial concentrations of A and B as given below:
A / mol L-1 | 0.20 | 0.20 | 0.40 |
B / mol L-1 | 0.30 | 0.10 | 0.05 |
ro / mol L-1 s-1 | 5.07 x 10-5 | 5.07 x 10-5 | 1.43 x 10-4 |
The order of the reaction with respect to A and B would be:
1. | The order with respect to A is 0.5 and with respect to B is zero. |
2. | The order with respect to A is 1 and with respect to B is 0.5 |
3. | The order with respect to A is 2 and with respect to B is 1 |
4. | The order with respect to A is 1.5 and with respect to B is zero |
For a reaction, 2A + B → C + D, the following observations were recorded:
Experiment | [A]/mol L-1 | [B]/mol L-1 | Initial rate of formation of D/mol L-1 min-1 |
I | 0.1 | 0.1 | 6.0 x 10-3 |
II | 0.3 | 0.2 | 7.2 x 10-2 |
III | 0.3 | 0.4 | 2.88 x 10-1 |
IV | 0.4 | 0.1 | 2.40 x 10-2 |
The rate law applicable to the above mentioned reaction would be:
1. Rate = k[A]2[B]3
2. Rate = k[A][B]2
3. Rate = k[A]2[B]
4. Rate = k[A][B]
Given the following observations:
Experiment | [A] / mol L-1 | [B] / mol L-1 | Initial rate / mol L-1 min-1 |
I | 0.1 | 0.1 | 2.0 x 10-2 |
II | X | 0.2 | 4.0 x 10-2 |
III | 0.4 | 0.4 | Y |
The reaction between A and B is first-order with respect to A and zero-order with respect to B. The values of X and Y are, respectively:
1. X = 0.2 \(mol\) \(L^{- 1}\); Y = \(\) \(0 . 08\) \(mol\) \(L^{- 1} \left(min\right)^{- 1}\)
2. X = 0.02 \(mol\) \(L^{- 1}\); Y = \(\) \(0 . 08\) \(mol\) \(L^{- 1} \left(min\right)^{- 1}\)
3. X = 0.01 \(mol\) \(L^{- 1}\); Y = \(\) \(0 . 8\) \(mol\) \(L^{- 1} \left(min\right)^{- 1}\)
4. X = 0.2 \(mol\) \(L^{- 1}\); Y = \(\) \(0 . 8\) \(mol\) \(L^{- 1} \left(min\right)^{- 1}\)
The rate constant of a radioactive substance is . The value of half-life will be :
1. 0.05 years
2. 0.17 years
3. 0.26
4. 1.6 years
During a nuclear explosion, one of the products is 90Sr with a half-life of 28.1 years. If 1µg of 90Sr was absorbed in the bones of a newly born baby instead of calcium, the amount of 90Sr that will remain after 10 years in the now grown up child would be -
(Given ,antilog(0.108)=1.28)
1. 0.227 µg
2. 0.781 µg
3. 7.81 µg
4. 2.27 µg