A parallel-plate capacitor of capacitance \(40 \mu F\) is connected to a \(100 V\) power supply. Now the intermediate space between the plates is filled with a dielectric material of dielectric constant \(K=2\). Due to the introduction of dielectric material, the extra charge and the change in the electrostatic energy in the capacitor, respectively, are
1. \(4~\text{mC}~\text{and}~0.2~\text J\)
2. \(2~\text{mC}~\text{and}~0.4~\text J\)
3. \(8~\text{mC}~\text{and}~2.0~\text J\)
4. \(2~\text{mC}~\text{and}~0.2~\text J\)