A certain quantity of water cools from 70 0C to 60 0C in the first 5 minutes and to 54 0C in the next 5 minutes. The temperature of the surroundings is:
1. 45oC
2. 20oC
3. 42oC
4. 10oC
| Assertion (A): | For small difference in absolute temperature, compared with the temperature itself, the net rate of transfer of energy from a body to its surrounding by radiation is directly proportional to the temperature difference. |
| Reason (R): | The net ratio of transfer of energy by radiation from a body (temperature \(T_b=T_S+\theta\)) to its surrounding (temperature \(T_S\)) is given by: \(\dfrac{dQ}{dt}=eA\sigma(T_b^4-T_S^4)\\ ~~~~~~~=eA\sigma\left\{(T_S+\theta)^4-T_S^4\right\}\\ ~~~~~~~\approx4eA\sigma T^3_S\theta,~\text{where }\theta\ll T_S.\) |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
| 1. | \(260\) s | 2. | \(280\) s |
| 3. | \(300\) s | 4. | \(320\) s |
The temperature of a body falls from 50 to 40 in 10 minutes. If the temperature of the surroundings is 20, then temperature of the body after another 10 minutes will be-
(1) 36.6
(2) 33.3
(3) 35
(4) 30
A body cools down from \(65^\circ \text{C}\) to \(60^\circ \text{C}\) in \(5\) minutes. It will cool down from \(60^\circ \text{C}\) to \(55^\circ \text{C}\) in:
| 1. | \(5\) minutes |
| 2. | less than \(5\) minutes |
| 3. | more than \(5\) minutes |
| 4. | less than or more than \(5\) minutes depending on whether its mass is more than or less than \(1~\text{kg}\) |