Radiation energy corresponding to the temperature T of the sun is E. If its temperature is doubled, then its radiation energy will be:
1. 32 E
2. 16 E
3. 8 E
4. 4 E

Subtopic:  Stefan-Boltzmann Law |
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Level 1: 80%+
AIPMT - 1998
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Two spheres \(A\) and \(B\) of same material having radius \(8\) cm and \(4\) cm are maintained at temperatures \(127^{\circ}\text{C}\) and \(527^{\circ}\text{C}\) respectively. The ratio of energy radiated by \(A\) and \(B\) is:
1. \(1:4\)
2. \(3:1\)
3. \(1:2\)
4. \(6:1\)
Subtopic:  Stefan-Boltzmann Law |
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Level 1: 80%+
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A black body is at a temperature of \(300~ \text{K}.\) The rate at which it emits energy is proportional to:
1. \((300)^1\) 2. \((300)^2\)
3. \((300)^3\) 4. \((300)^4\)
Subtopic:  Stefan-Boltzmann Law |
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A black body is at \(727^\circ\text{C}.\) The rate at which it emits energy is proportional to:

1. \((727)^2\) 2. \((1000)^4\)
3. \((1000)^2\) 4. \((727)^4\)
Subtopic:  Stefan-Boltzmann Law |
 82%
Level 1: 80%+
AIPMT - 2007
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A spherical black body of radius \(10~\text{cm}\) radiates \(100~\text{W}\) power at \(400~\text K.\) If the radius were halved and the temperature doubled, the power radiated in watts would be:
1. \(100\)
2. \(200\)
3. \(400\)
4. \(800\)
Subtopic:  Stefan-Boltzmann Law |
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The radius of a spherical black body is \(R,\) and \(\alpha\) represents the rate of energy production within the body. The temperature of the given black body in a steady-state is: (where \(\sigma\) is Stefan- Boltzmann constant)
1. \(\left(\dfrac{\alpha}{\sigma \times 4 \pi R^2}\right)^{\dfrac{1}{4}} \) 2. \(\left(\dfrac{\sigma \times 4 \pi R^2}{\alpha}\right)^{\dfrac{1}{4}}\)
3. \(\left(\dfrac{\alpha}{\sigma \times 4 \pi R^2}\right)\) 4. \(\left(\dfrac{4 \pi R^2 \times \sigma}{\alpha}\right)\)
Subtopic:  Stefan-Boltzmann Law |
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Two bodies A and B have thermal emissivities of 0.01 and 0.81 respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength λB of B corresponding to maximum spectral radiancy in the radiation differs from that of A by 1.00 µm. If the temperature of A is 5802 K:

1. the temperature of B is 17406 K.

2. λB = 1.5 µm

3. the temperature of B is 11604 K.

4. the temperature of B is 2901 K.

Subtopic:  Stefan-Boltzmann Law | Wien's Displacement Law |
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Unit of Stefan's constant is:

1. Watt-m2-K4

2. Watt-m2/K4

3. Watt/m2–K

4. Watt/m2 K4

Subtopic:  Stefan-Boltzmann Law |
 80%
Level 1: 80%+
AIPMT - 2002
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The absolute temperature of a star increases from \(T\) to \(2T\) while the radius of the star shrinks from \(R\) to \(R/2\). As a result, the total power radiated by the star:
1. increases by a factor of \(16\)
2. decreases by a factor of \(4\)
3. remains constant
4. increases by a factor of \(4\)
Subtopic:  Stefan-Boltzmann Law |
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Level 2: 60%+
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