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Q. No.The position vector of a particle changes with time according to the relation,
\(\vec{r}(t)=(15 t^2) \hat{i}+\left(4-20 t^2\right) \hat{j},\) where \(\vec{r}(t)\) is in metres and \(t\) is in seconds.
What is the magnitude of the acceleration at \(t=1\) second?
\(\vec{r}(t)=(15 t^2) \hat{i}+\left(4-20 t^2\right) \hat{j},\) where \(\vec{r}(t)\) is in metres and \(t\) is in seconds.
What is the magnitude of the acceleration at \(t=1\) second?
| 1. | \(100\) m/s2 | 2. | \(40\) m/s2 |
| 3. | \(50\) m/s2 | 4. | \(25\) m/s2 |
Subtopic: Â Acceleration |
 85%
Level 1: 80%+
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If the position vector of a particle is given by \(\overrightarrow{r}\left({t}\right){=}({8}{t}\hat{i}{+}{5}{t}^{2}\hat{j}{+}{6}\hat{k}),\) then the correct statement about the acceleration of the particle is:
| 1. | It is along the positive \(\mathrm{y \text-}\)axis. |
| 2. | It is along the positive \(\mathrm{x \text-}\)axis. |
| 3. | It is equally inclined to \(\mathrm{x}\) and \(\mathrm{y \text-}\)axis. |
| 4. | It is along the positive \(\mathrm{z \text-}\)axis. |
Subtopic: Â Acceleration |
 72%
Level 2: 60%+
JEE
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