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Q. No.Considering the formation, breaking and strength of hydrogen bond, predict which of the following mixtures will show a positive deviation from Raoult’s law?
1. Methanol and acetone
2. Chloroform and acetone
3. Nitric acid and water
4. Phenol and aniline
Subtopic: Azeotrope |
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A mixture of ethanol and water shows a positive deviation from Raoult's law. This mixture also forms an azeotropic mixture. The boiling point of this azeotropic mixture will be
| 1. | Less than the boiling point of water but more than the boiling point of ethanol |
| 2. | More than the boiling point of water but less than the boiling point of ethanol |
| 3. | More than the boiling point of ethanol as well as water |
| 4. | Less than the boiling point of ethanol as well as water |
Subtopic: Azeotrope |
70%
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If A (volatile solute) and B (volatile solvent) form an azeotropic mixture then the correct statement regarding the above azeotropic mixture will be -
| 1. | Mole fraction of A in the vapour phase is more than the mole fraction of A or B in liquid phase |
| 2. | Mole fraction of A or B in the vapour phase is more than the mole fraction of A or B in liquid phase |
| 3. | Mole fraction of A or B in the vapour phase is same as the mole fraction of A or B in liquid phase |
| 4. | Mole fraction of A and B in the vapour phase is less than the mole fraction of A or B in liquid phase |
Subtopic: Azeotrope |
65%
From NCERT
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