Hydrocarbon (A) reacts with bromine by substitution reaction to form an alkyl bromide B. B undergoes the Wurtz reaction to give a gaseous hydrocarbon containing less than four carbon atoms.

The formula of (A) is-

1. $\mathrm{CH}\equiv \mathrm{CH}$
2. ${\mathrm{CH}}_2={\mathrm{CH}}_2$ 
3. ${\mathrm{CH}}_3-{\mathrm{CH}}_3$
4. ${\mathrm{CH}}_4$

The compound ${\mathrm{C}}_7{\mathrm{H}}_8$ undergoes the following reactions

${\mathrm{C}}_7{\mathrm{H}}_8\stackrel{3{\mathrm{Cl}}_2/\mathrm{hv}}{\to }\mathrm{A}\stackrel{{\mathrm{Br}}_2/\mathrm{Fe}}{\to }\mathrm{B}\stackrel{\mathrm{Zn}/\mathrm{HCl}}{\to }$ C

The product 'C' is-

1. m–Bromotoluene

2. o–Bromotoluene

3. 3–Bromo–2,4,6–trichlorotoluene

4. p–Bromotoluene

P, Q, and R in the above-mentioned sequence of reactions are respectively:

1.
2.
3.
4.

The molecule among the following that has the hybridization ${\mathrm{sp}}^2, {\mathrm{sp}}^2, \mathrm{sp},\; and \mathrm{sp}$ from left to right atoms is-

1. $\mathrm{HC}\equiv \mathrm{C}-\mathrm{C}\equiv \mathrm{H}$

2. ${\mathrm{CH}}_2=\mathrm{CH}-\mathrm{C}\equiv \mathrm{CH}$

3. ${\mathrm{CH}}_2=\mathrm{CH}-\mathrm{CH}={\mathrm{CH}}_2$ 

4. ${\mathrm{CH}}_2-\mathrm{CH}=\mathrm{CH}-{\mathrm{CH}}_3$

Predict the correct intermediate and product in the following reaction.

H₃C-C$\equiv$CH $\underset{{\mathrm{HgSO}}_4}{\overset{{\mathrm{H}}_2\mathrm{O},}{\to }}$ ${\mathrm{H}}_2{\mathrm{SO}}_4$ Intermediate $\to$Product

                                                    (A)                   (B)

The correct order of acidity is-

Which of the following compounds shall not produce propene by reaction with HBr followed by elimination or direct only elimination reaction?

1.
2.
3.
4.

In the given reaction 
 
The product P is:

1.		2.
3.		4.

The compound that will react most readily with gaseous bromine has the formula: