Two masses as shown are suspended from a massless pulley. What would be the acceleration of the system when masses are left free?

1. \(2g/3\)
2. \(g/3\)
3. \(g/9\)
4. \(g/7\)
(where \(g\) is the acceleration due to gravity.)

If force \(F=500-100t,\) then the function of impulse with time will be:
1. \( 500 t-50 t^2 \)
2. \( 50 t-10 \)
3. \( 50-t^2 \)
4. \( 100 t^2\)
 

A person standing on a spring balance inside a stationary lift measures \(60~\text{kg}\). The weight (in N) of that person if the lift descends with the uniform downward acceleration of \(1.8~\text{m/s}^2\) will be: [\(g=10~\text{m/s}^2\)]
1. \(600~\text{N}\)
2. \(500~\text{N}\)
3. \(492~\text{N}\)
4. \(450~\text{N}\)

A person of mass 60 kg is inside a lift of mass 940 kg and presses the button on control panel. The lift starts moving upwards with an acceleration $1.0$ $\mathrm{m}/{\mathrm{s}}^2$. If $\mathrm{g}=10$ $\mathrm{m}/{\mathrm{s}}^2$, the tension in the supporting cable is:

1. 9680 N

2. 11000 N

3. 1200 N

4. 8600 N

Pulley and strings shown in the figure are massless. Acceleration of 3 kg block is: [Take g = 10 $\mathrm{m}/{\mathrm{s}}^2$]

(1) 1 $\mathrm{m}/{\mathrm{s}}^2$

(2) 2 $\mathrm{m}/{\mathrm{s}}^2$

(3) 3 $\mathrm{m}/{\mathrm{s}}^2$

(4) 4 $\mathrm{m}/{\mathrm{s}}^2$

The motion of a particle of mass \(m\) is described by \(y=ut+\frac{1}{2}gt^{2}.\)  The force acting on the particle is: 
1. \(3mg\)
2. \(mg\)
3. \(\frac{mg}{2}\)
4. \(2mg\)