The x and y coordinates of the particle at any time are $\mathrm{x}=<mspace\; width="1em"></mspace>5\mathrm{t}-2{\mathrm{t}}^2$ and y= 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t= 2 sec is:

The x and y coordinates of the particle at any time are x=5t-2$t^2$ and y=10t respectively, where x and y are in the metres and t is in seconds. The acceleration of the particle at t=2s is :

1. 0

2. 5$m/s^2$

3. -4$m/s^2$

4. -8 $m/s^2$

The position vector of a particle \(\vec{r}\) as a function of time \(t\) (in seconds) is \(\vec{r}=(3t) \hat{i}+(2t^2) \hat{j}\) m. The initial acceleration of the particle is:

The \(x\) and \(y\) coordinates of the particle at any time are \(x = 5t-2t^2\) and \(y=10t\) respectively, where \(x\) and \(y\) are in metres and \(t\) is in seconds. The acceleration of the particle at \(t=2\) s is:
1. \(0\) m/s²
2. \(5\) m/s²
3. \(-4\) m/s²
4. \(-8\) m/s²

A body is moving with velocity 30 m/s towards east. After 10 s its velocity becomes 40 m/s towards north. The average acceleration of the body is

(1) $7<mspace\; width="1em"></mspace>\mathrm{m}/{\mathrm{s}}^2$                                             

(2) $\sqrt{7}<mspace\; width="1em"></mspace>\mathrm{m}/{\mathrm{s}}^2$

(3) $5<mspace\; width="1em"></mspace>\mathrm{m}/{\mathrm{s}}^2$                                             

(4) $1<mspace\; width="1em"></mspace>\mathrm{m}/{\mathrm{s}}^2$