The displacement of a particle is represented by the equation \(s=\left(3 t^{3}+7 t^{2}+5 t+8\right)\) where \(s\) is in metre and \(t\) in seconds. The acceleration of the particle at \(t=1\) second is:
1. zero 2. \(14~\text{m/s}^2\)
3. \(18~\text{m/s}^2\) 4. \(32~\text{m/s}^2\)
Subtopic:  Acceleration |
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A car is going up a slight slope decelerating at \(0.1\) m/s2. It comes to a stop after going for \(5\) s. What was its initial velocity? 
1. \(0.02~\text {m/s}\)
2. \(0.25~\text {m/s}\)
3. \(0.5~\text{m/s}\)
4. \(1.0~\text{m/s}\)
Subtopic:  Acceleration |
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The position of a particle as a function of time \(t\), is given by;
\(x(t)=a t+b t^2-c t^3\)
where \(a\), \(b\) and \(c\) are constants. When the particle attains zero acceleration, then its velocity will be:
1. \( a+\frac{b^2}{4 c} \)
2. \( a+\frac{b^2}{c} \)
3. \( a+\frac{b^2}{3 c} \)
4. \( a+\frac{b^2}{2 c}\)

Subtopic:  Acceleration |
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JEE
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A scooter accelerates from rest for time t1 at constant rate a1 and then retards at constant rate a2 for time t2 and comes to rest. The correct value of t1t2 will be :

1. a1+a2a2

2. a2a1

3. a1a2

4. a1+a2a1

Subtopic:  Acceleration |
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The displacement x of a particle along a straight line at time t is given by x=a0+a1t+a2t2. The acceleration of the particle is

(1)  a0

(2)  a1

(3)  2a2

(4)  a2

Subtopic:  Acceleration |
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The acceleration α of a particle starting from rest varies with time according to relation a=αt+β. The velocity of the particle after a time t will be

1.  αt22+β

2.  αt22+βt

3.  αt2+12βt

4.  αt2+β2

Subtopic:  Acceleration |
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A particle starts from rest at t=0 and undergoes an acceleration a in ms-2 with time t in second which is as shown

                   

Which one of the following plot represents velocity v in ms-1 versus time t in second?

1.  

2.  

3.  

4.  

Subtopic:  Acceleration |
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The position x of a particle varies with time (t) as x=at2-bt3. The acceleration at time t of the particle will be equal to zero, where t is equal to

1. 2a3b

2. ab

3. a3b

4. zero

Subtopic:  Acceleration |
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The motion of a particle along a straight line is described by the equation \(x = 8+12t-t^3\) where \(x \) is in meter and \(t\) in seconds. The retardation of the particle, when its velocity becomes zero, is:

1. \(24\) ms-2 2. zero
3. \(6\) ms-2 4. \(12\) ms-2
Subtopic:  Acceleration |
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AIPMT - 2012
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The position x of particle varies with time t as x=at2-bt3. The acceleration of the particle will be zero at time equal to

(1)  ab

(2)  2ab

(3)  a3b

(4)  Zero

Subtopic:  Acceleration |
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