premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

Point charge q moves from point P to point S along the path PQRS (figure shown) in a uniform electric field E pointing co-parallel to the positive direction of the x-axis. The coordinates of the points P, Q, R, and S are (a,b,0),(2a,0,0),(a,b,0) and (0, 0, 0) respectively. The work done by the field in the above process is given by the expression 

(1) qEa

(2) – qEa

(3) qEa2

(4) qE[(2a)2+b2]

Subtopic:  Energy of Dipole in an External Field |
Level 3: 35%-60%
Hints

An electric dipole is place at an angle of \(30^{\circ}\) with an electric field intensity \(2\times10^{5}~\text{N/C}\). It experiences a torque equal to \(4~\text{N-m}\). The charge on the dipole, if the dipole length is \(2~\text{cm}\), is: 
1. \(8~\text{mC}\)
2. \(2~\text{mC}\)
3. \(5~\text{mC}\)
4. \(7~\mu\text{C}\)

Subtopic:  Energy of Dipole in an External Field |
 87%
Level 1: 80%+
NEET - 2016
Hints
Links

An electric dipole of moment \(p\) is placed in an electric field of intensity \(E.\) The dipole acquires a position such that the axis of the dipole makes an angle \(\theta\) with the direction of the field. Assuming that the potential energy of the dipole to be zero when \(\theta = 90^{\circ}\), the torque and the potential energy of the dipole will respectively be:
1. \(pE\text{sin}\theta, ~-pE\text{cos}\theta\)
2. \(pE\text{sin}\theta, ~-2pE\text{cos}\theta\)
3. \(pE\text{sin}\theta, ~2pE\text{cos}\theta\)
4. \(pE\text{cos}\theta, ~-pE\text{sin}\theta\)

Subtopic:  Energy of Dipole in an External Field |
 84%
Level 1: 80%+
AIPMT - 2012
Hints
Links

An electric dipole of moment \(\vec {p} \) is lying along a uniform electric field \(\vec{E}.\) The work done in rotating the dipole by \(90^{\circ}\) is:
1. \(\sqrt{2}pE\)
2. \(\dfrac{pE}{2}\)
3. \(2pE\)
4. \(pE\)

Subtopic:  Energy of Dipole in an External Field |
 83%
Level 1: 80%+
AIPMT - 2006
Hints
Links

A short electric dipole has a dipole moment of \(16 \times 10^{-9} ~\text{C-}\text{m}. \) The electric potential due to the dipole at a point at a distance of \(0.6~\text{m}\) from the centre of the dipole situated on a line making an angle of \(60^{\circ}\) with the dipole axis is:
\(\left( \dfrac{1}{4\pi \varepsilon_0}= 9\times 10^{9}~\text{N-m}^2/\text{C}^2 \right) \)

1. \(200~\text{V}\) 2. \(400~\text{V}\)
3. zero 4. \(50~\text{V}\)
Subtopic:  Energy of Dipole in an External Field |
 69%
Level 2: 60%+
NEET - 2020
Hints
Links

An electric dipole of length 2 cm is placed with its axis making an angle of 30° to a uniform electric field 105N/C. If it experiences a torque of 103Nm, then the potential energy of the dipole:

1. -10 J

2. -20 J

3. -30 J

4. -40 J

Subtopic:  Energy of Dipole in an External Field |
 72%
Level 2: 60%+
Hints

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

A molecule of a substance has a permanent electric dipole moment of magnitude 10–29 C m. A mole of this substance is polarised (at low temperature) by applying a strong electrostatic field of magnitude 106 V m–1. The direction of the field is suddenly changed by an angle of 600. The heat released by the substance in aligning its dipoles along the new direction of the field is: (For simplicity, assume 100% polarisation of the sample).

1. 6 J

2. 8 J

3. 3 J

4. 4 J

Subtopic:  Energy of Dipole in an External Field |
 54%
Level 3: 35%-60%
Hints
Links

An electric dipole of moment p is placed parallel to the uniform electric field. The amount of work done in rotating the dipole by 900 is-
1.  2pE
2.  pE
3.  pE/2
4.  Zero

Subtopic:  Energy of Dipole in an External Field |
 79%
Level 2: 60%+
Hints

An electric dipole is placed as shown in the figure.

The electric potential (in \(10^2~\text{V}\)) at the point \(P\) due to the dipole is:
(\(\varepsilon_0=\) permittivity of free space and \(\dfrac{1}{4 \pi \varepsilon_0}=k\))
1. \(\left(\dfrac{8}{3}\right)qk\) 2. \(\left(\dfrac{3}{8}\right)qk \)
3. \(\left(\dfrac{5}{8}\right)qk\) 4. \(\left(\dfrac{8}{5}\right)qk\)
Subtopic:  Energy of Dipole in an External Field |
 65%
Level 2: 60%+
NEET - 2023
Hints