At the interface between two materials having refractive indices \({n}_1\) and \({n}_2\), the critical angle for reflection of an electromagnetic wave is \(\theta_{1c} \). The \({n}_2\) material is replaced by another material having refractive index \({n}_3\) such that the critical angle at the interface between \({n}_1\) and \({n}_3\) materials is \(\theta_{2c}\). If \({n}_3>{n}_2>{n}_1 \); \(n_2 / n_3=2 / 5 \) and \(\sin \theta_{2 c}-\sin \theta_{1 c}=1 / 2 \) then \(\theta_{1c}\) is:
1. \(\sin ^{-1}\left(\dfrac{5}{6 n_1}\right) \)
2. \(\sin ^{-1}\left(\dfrac{2}{3 n_1}\right) \)
3. \(\sin ^{-1}\left(\dfrac{1}{3 n_1}\right) \)
4. none of these